You can use Data.Sequence.fromList to go [a] -> Seq a, though.
So given
f :: Monad m => a -> m b
you have
import Data.Traversable as T
import Data.Sequence as S
g :: Monad m => [a] -> m (S.Seq b)
g = T.mapM f . S.fromList
- ryan
On Wed, Sep 28, 2011 at 6:20 PM, Marc Ziegert wrote:
> Hi T
Hi Thomas,
this should be on the haskell-cafe or haskell-beginners mailing list.
Haskell@... is mainly for announcements.
You have:
> f :: Monad m =>
> a -> m b
> Data.Traversable.mapM :: (Monad m, Traversable t) =>
> (a -> m b) -> t a -> m (t b)
So, if you define
