That's why I said for appropriate g and f. But I see that my
wording was misleading.
However you can say:
foldl' oplus alpha bs =(foldr f id bs) alpha where
f a g = \alpha - g (alpha `oplus` a)
foldr' oplus alpha bs = (foldl f id bs) alpha where
f g a = \alpha - g (a `oplus`
Adrian,
That's why I said for appropriate g and f. But I see that my
wording was misleading.
Thanks for following up! I had thought you were arguing that foldl and
foldr were easily and intuitively interchangeable; they're surely not so
for beginners.
Now I think you're arguing that given
