Thanks Mat, it works, but I still have a problem: I'm heavily using
Data.Binary.encode for various types (Int32, Int8, String, Bool...)
and I don't know how I should manage this using
Data.ByteString.Lazy.Char8.
--
Cp
On Sat, Nov 20, 2010 at 22:35, Mathias Weber mat_we...@t-online.de wrote:
Then how about using encode (as in your original example) and decode
(both from Data.Binary). IMO it's garanteed that decode . encode = id
(at least for the standard types).
...
decrypt :: Data.ByteString.Lazy.ByteString - String
decrypt = decode . Crypto.decrypt privKey
...
Am 21.11.2010
Charles-Pierre Astolfi cpa at crans.org writes:
Hi -cafe,
I have a question about Codec.Crypto.RSA: how to enforce that
(informally) decrypt . encrypt = id
Consider this code:
That's certainly what I would expect and one of the unit tests that comes with
Here's a working example:
import qualified Codec.Crypto.RSA as Crypto
import System.Random (mkStdGen)
import Data.Binary (encode)
import Data.ByteString.Lazy.UTF8 (toString)
n = 1024
(pubKey,privKey,_) = Crypto.generateKeyPair (mkStdGen n) n
encrypt :: (Data.Binary.Binary a) = a -
Charles-Pierre Astolfi wrote:
Here's a working example:
import qualified Codec.Crypto.RSA as Crypto
import System.Random (mkStdGen)
import Data.Binary (encode)
import Data.ByteString.Lazy.UTF8 (toString)
n = 1024
(pubKey,privKey,_) = Crypto.generateKeyPair (mkStdGen n) n
encrypt ::
The problem in this example is the use of Data.Binary. When using
Data.ByteString.Lazy.Char8 instead, the problem does not exist.
import qualified Codec.Crypto.RSA as Crypto
import System.Random (mkStdGen)
import Data.ByteString.Lazy.UTF8 (toString)
import qualified Data.ByteString.Lazy.Char8 as
