Hi -cafe,
I'm using readProcess and I don't know how to handle this issue:
readProcess cmd [opt1,opt2] seems to execute the following:
$ cmd opt1 opt2
That is usually fine, but I'm using an external program that doesn't
understand the quotes, so I need to execute instead:
$ cmd opt1 opt2
How
Quoth Charles-Pierre Astolfi c...@crans.org,
readProcess cmd [opt1,opt2] seems to execute the following:
$ cmd opt1 opt2
That is usually fine, but I'm using an external program that doesn't
understand the quotes, so I need to execute instead:
$ cmd opt1 opt2
How should I do that?
I think
Am 11.08.2011 16:45, schrieb Charles-Pierre Astolfi:
Hi -cafe,
I'm using readProcess and I don't know how to handle this issue:
readProcess cmd [opt1,opt2] seems to execute the following:
are you sure that your argument strings do not contain the quotes,
possibly by calling show on
I've found my mistake: I was calling readProcess cmd [-p -t] instead
of readProcess cmd [-p,-t]
Not sure what are the semantics of quotation in this case, though. And
I'm pretty sure my analysis is wrong because of that :)
--
Cp
On Thu, Aug 11, 2011 at 16:05, Donn Cave d...@avvanta.com wrote:
Quoth Charles-Pierre Astolfi c...@crans.org,
I've found my mistake: I was calling readProcess cmd [-p -t] instead
of readProcess cmd [-p,-t]
That would do it.
Not sure what are the semantics of quotation in this case, though. And
I'm pretty sure my analysis is wrong because of that :)
The
On Thu, Aug 11, 2011 at 11:29, Charles-Pierre Astolfi c...@crans.org wrote:
I've found my mistake: I was calling readProcess cmd [-p -t] instead
of readProcess cmd [-p,-t]
Not sure what are the semantics of quotation in this case, though. And
I'm pretty sure my analysis is wrong because of
