Ryan Ingram discussed a question of writing
fs f g = (f fst, g snd)
so that fs ($ (1, 2)) type checks.
This is not that difficult:
{-# LANGUAGE RankNTypes, MultiParamTypeClasses -#}
{-# LANGUAGE FunctionalDependencies, FlexibleInstances #-}
class Apply f x y | f x - y where
apply ::
Erik de Castro Lopo mle...@mega-nerd.com writes:
Finally, if a package is deprecated it might be usefult to have
a reason as well so the hackage entry might say:
Deprecated : true (replaced by package XXX)
or
Deprecated : true (needs maintainer)
Or just Deprecated: (reason)?.
Henk-Jan van Tuyl wrote:
I tried to compile base-4.0.0.0 (on Windows XP) as follows:
[...]\base\4.0.0.0runhaskell Setup configure
command line: module `Prelude' is not loaded
It seems that Base needs another way to compile, how?
AFAIK base is shipped with GHC, and cannot be compiled
On Mon, Jun 8, 2009 at 20:39, John Millikinjmilli...@gmail.com wrote:
I'm trying to convert an XML document, incrementally, into a sequence
of XML events. A simple example XML document:
doc xmlns=org:myproject:mainns xmlns:x=org:myproject:otherns
titleDoc title/title
x:refabc1234/x:ref
Hi everyone,
Tonight there will be another meeting of the Dutch Haskell Users'
Group! This time we'll meet in Amsterdam, in the library. On the wiki
[1] you can find the details of how to reach it. We'll be at the top
floor and shouldn't be hard to recognize. The meeting is set to begin
And just to provide an example of working program:
---
module Main where
import Text.XML.Expat.Qualified
import Text.XML.Expat.Namespaced
import Text.XML.Expat.Tree
import qualified Data.ByteString.Lazy as BSL
main = do
f - BSL.readFile doc1.xml
let (tree,error) = parseTree
Hi,
I have the following code:
---
{-# LANGUAGE RankNTypes #-}
f :: ((forall a. a - a) - b) - b
f x = x id
g :: (forall c. Eq c = [c] - [c]) - ([Bool],[Int])
g y = (y [True], y [1])
h :: ([Bool],[Int])
h = f g
Hi,
I am using the System.Random method randomRIO. How can I convert its output
to an Int?
Thanks...
--
View this message in context:
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Sent from the Haskell - Haskell-Cafe mailing list archive at Nabble.com.
You can not convert an IO Int to Int, or at least, you shouldn't.
However, you can do as follows:
test :: IO ()
test = do
int - randomRIO -- or whatever it is called
print $ useInt int
useInt :: Int - Int
useInt x = x+10
//Tobias
2009/6/9 ptrash ptr...@web.de:
Hi,
I am using the
ptrash wrote:
Hi,
I am using the System.Random method randomRIO. How can I convert its output
to an Int?
Thanks...
You cannot [1], you should read up on monads and I/O in Haskell, for example
http://haskell.org/haskellwiki/IO_inside
[1] Yes, you can, but no, you don't want to.
Regards,
On 2009/06/09, at 19:33, Tobias Olausson wrote:
You can not convert an IO Int to Int, or at least, you shouldn't.
However, you can do as follows:
test :: IO ()
test = do
int - randomRIO -- or whatever it is called
print $ useInt int
useInt :: Int - Int
useInt x = x+10
Or, you can
One more example:
This does not type-check:
---
{-# LANGUAGE RankNTypes, ImpredicativeTypes #-}
f :: [forall a. t a - t a] - t b - t b
f = foldr (.) id
---
Couldn't match expected type
Sterling Clover s.clover at gmail.com writes:
Try it with the following type signature and it should work fine:
convert :: (Data a) = Int - a - a
Of course, as has been noted, SYB is a rather big sledgehammer for
the insect in question.
Cheers,
S.
Thank you Sterling. That is
Ok, thanks for the information.
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___
Haskell-Cafe mailing list
Hi,
I have the following two lists:
a = [1,2,3]
b = [A,B,C]
I want a combination of the to lists:
c = [(1,A), (2, B), (3, C)]
How can I do this?
I have tried
c = [(x,y) | x - a, y - b]
But this just returns me a list with every possible combination of the 2
lists.
Thanks...
--
View
Try c = zip a b
On Tue, Jun 9, 2009 at 9:05 AM, ptrash ptr...@web.de wrote:
Hi,
I have the following two lists:
a = [1,2,3]
b = [A,B,C]
I want a combination of the to lists:
c = [(1,A), (2, B), (3, C)]
How can I do this?
I have tried
c = [(x,y) | x - a, y - b]
But this just
Probably you might need the zip function.Check
here:http://haskell.org/ghc/docs/latest/html/libraries/base/Prelude.html#v:zip
Date: Tue, 9 Jun 2009 06:05:57 -0700
From: ptr...@web.de
To: haskell-cafe@haskell.org
Subject: [Haskell-cafe] Combine to List to a new List
Hi,
I have the
Hey, cool. Thanks!
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Hi Toby,
Thanks for the helpful comments. I'd gotten used to arithmetic operator
sections (+2), (*2), etc. but hadn't picked up on the generality of using them
with *any* infix function. I can also see the benefit of using List.Group.
However, I'm uncertain about how to import just fromList
On Tue, 2009-06-09 at 06:05 -0700, ptrash wrote:
Hi,
I have the following two lists:
a = [1,2,3]
b = [A,B,C]
I want a combination of the to lists:
c = [(1,A), (2, B), (3, C)]
How can I do this?
What you want is a function with the following type signature:
[t1] - [t2] - [(t1,t2)]
On Tue, Jun 9, 2009 at 15:23, michael ricenowg...@yahoo.com wrote:
import Data.Map (Map) (fromList,!) ???
import qualified Data.Map as Map (fromList,!) ???
Because ! is an operator, you need to enclose it in parentheses. Also,
the (Map) in the import is already the list of things you are
Hmm...it am not getting through it. I just want to generate a random number
and then compare it with other numbers. Something like
r = randomRIO (1, 10)
if (r 5) then... else ...
--
View this message in context:
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Sent from
On Tue, Jun 9, 2009 at 2:52 PM, ptrashptr...@web.de wrote:
Hmm...it am not getting through it. I just want to generate a random number
and then compare it with other numbers. Something like
r = randomRIO (1, 10)
if (r 5) then... else ...
You have to do it inside the IO monad, something
On Tue, 9 Jun 2009, ptrash wrote:
I am using the System.Random method randomRIO. How can I convert its output
to an Int?
in general:
http://haskell.org/haskellwiki/How_to_get_rid_of_IO
about randomIO:
http://haskell.org/haskellwiki/Avoiding_IO#State_monad
Am Dienstag 09 Juni 2009 15:57:24 schrieb Magnus Therning:
On Tue, Jun 9, 2009 at 2:52 PM, ptrashptr...@web.de wrote:
Hmm...it am not getting through it. I just want to generate a random
number and then compare it with other numbers. Something like
r = randomRIO (1, 10)
if (r 5)
John Millikin wrote:
On Mon, Jun 8, 2009 at 3:39 PM, Henning
Thielemannlemm...@henning-thielemann.de wrote:
I think you could use the parser as it is and do the name parsing later.
Due to lazy evaluation both parsers would run in an interleaved way.
I've been trying to figure out how to get
In the import statements, it wasn't clear to me that I could import types as
well as functions, and Map is a type. All clear now.
Thanks.
Michael
--- On Tue, 6/9/09, Thomas ten Cate ttenc...@gmail.com wrote:
From: Thomas ten Cate ttenc...@gmail.com
Subject: Re: [Haskell-cafe] Applying
Andy Stewart wrote:
So have a better solution to avoid write above ugly code
How about:
data Page a =
Page {pageName :: IORef String
,pageId:: Int
,pageBuffer:: a
,pageBox :: VBox
}
class PageBuffer a where
pageBufferClone :: a -
Hi all,
I have below source code, i use Dynamic for `pageBuffer`.
In implement of function `pageClone`, after `case pt of`, i need write
like this, and this code looks ugly, if `PageTyep` have 100 type, i need
write those ugly code 100 times.
case pt of
TStringBuffer -
On Tue, Jun 9, 2009 at 16:14, Daniel Fischerdaniel.is.fisc...@web.de wrote:
Am Dienstag 09 Juni 2009 15:57:24 schrieb Magnus Therning:
On Tue, Jun 9, 2009 at 2:52 PM, ptrashptr...@web.de wrote:
Hmm...it am not getting through it. I just want to generate a random
number and then compare it
Magnus Therning writes:
ptrash wrote:
...am not getting through it. I just want to generate a random number
and then compare it with other numbers. Something like
r = randomRIO (1, 10)
if (r 5) then... else ...
You have to do it inside the IO monad, something like
myFunc = do
Hello jerzy,
Tuesday, June 9, 2009, 8:23:04 PM, you wrote:
Please, tell him first about random streams, which he can handle without
IO. Or, about ergodic functions (hashing contraptions which transform ANY
parameter into something unrecognizable). When he says : I know all that,
THEN hurt
All I want to do is split on commas, but not the commas inside () or tags.
I have been wanting to master parsec for a long time and this simple
exercise looked like a good place to start.
The code below does the right thing. Am I missing any tricks to make
this simpler/neater?
Thanks, thomas.
2009/6/6 Bertram Felgenhauer bertram.felgenha...@googlemail.com:
Interesting. This was changed in response to
http://hackage.haskell.org/trac/ghc/ticket/2528
| Tue Sep 2 11:29:50 CEST 2008 Simon Marlow marlo...@gmail.com
| * #2528: reverse the order of args to (==) in nubBy to match
Bulat Ziganshin wrote:
Hello jerzy,
Tuesday, June 9, 2009, 8:23:04 PM, you wrote:
Please, tell him first about random streams, which he can handle without
IO. Or, about ergodic functions (hashing contraptions which transform ANY
parameter into something unrecognizable). When he says : I
Am Dienstag 09 Juni 2009 20:29:09 schrieb Thomas Hartman:
All I want to do is split on commas, but not the commas inside () or
tags.
I have been wanting to master parsec for a long time and this simple
exercise looked like a good place to start.
The code below does the right thing. Am I
2009/6/9 Krzysztof Skrzętnicki gte...@gmail.com
On Tue, Jun 9, 2009 at 16:14, Daniel Fischerdaniel.is.fisc...@web.de
wrote:
If you're doing much with random generators, wrap it in a State monad.
To avoid reinventing the wheel one can use excellent package available
on Hackage:
On Tue, Jun 9, 2009 at 7:21 AM, Neil Brownnc...@kent.ac.uk wrote:
data Page a =
Page {pageName :: IORef String
,pageId :: Int
,pageBuffer :: a
,pageBox :: VBox
}
class PageBuffer a where
pageBufferClone :: a - IO (a, VBox)
pageClone ::
Dear all,
This post is partly a gripe about how poor the formal documentation
for various GHC extensions is, partly a gripe about how GHC blurs the
lines between syntactic and type-level issues as well as between
various extensions, and partly a gripe about how the Haskell 98 report
is sometimes
Hi,
you may also want to look at:
http://hackage.haskell.org/cgi-bin/hackage-scripts/package/xml
It knows about namespaces and, also, it's parser is lazy.
-Iavor
On Mon, Jun 8, 2009 at 11:39 AM, John Millikinjmilli...@gmail.com wrote:
I'm trying to convert an XML document, incrementally, into a
Thanks. It seems my original parser also works against FOO,BAR,BAZ if
you only modify
atom = string ,
| ( many1 $ noneOf (), ) -- add ,
Indeed, what to call the thingies in a parser is a source of some
personal consternation.
What is a token, what is an atom, what is an expr? It all
Paul L nine...@gmail.com wrote in article
856033f20906082224s2b7d5391gdc7a4ed913004...@mail.gmail.com in
gmane.comp.lang.haskell.cafe:
The open question is whether there exists such a
solution that's both elegant and efficient at maintain proper sharing
in the object language.
What is your
I'm very new to haskell hugs and would appreciate it if someone could help me
out here. I've been giving 2 questions.
1.) A and B are two sets of integers. Implement a function to obtain the
integers that belong to both sets.
Test your function fully.
2.) Define and test a function f, which,
haonan21 wrote:
I'm very new to haskell hugs and would appreciate it if someone could help me
out here. I've been giving 2 questions.
1.) A and B are two sets of integers. Implement a function to obtain the
integers that belong to both sets.
Test your function fully.
2.) Define and test a
On Mon, Jun 8, 2009 at 10:18 PM, Iavor Diatchki iavor.diatc...@gmail.comwrote:
OK, I think that I found and fixed the problem. As Thomas pointed
out, the configure script is not wrong. The problem turned out to be
the foreign import for getnameinfo (this was the missing symbol).
So it was
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