Re: forall quantifier

2003-06-06 Thread Ralf Hinze
Am Freitag, 6. Juni 2003 09:15 schrieb Simon Peyton-Jones: I forget whether I've aired this on the list, but I'm seriously thinking that we should change 'forall' to 'exists' in existential data constructors like this one. One has to explain 'forall' every time. But we'd lose a keyword. Or

Re: forall quantifier

2003-06-06 Thread Christian Maeder
I forget whether I've aired this on the list, but I'm seriously thinking that we should change 'forall' to 'exists' in existential data constructors like this one. One has to explain 'forall' every time. But we'd lose a keyword. exists (like forall in ghc only) could be used independently in a

Re: forall quantifier

2003-06-06 Thread Jon Fairbairn
On 2003-06-06 at 08:15BST Simon Peyton-Jones wrote: I forget whether I've aired this on the list, but I'm seriously thinking that we should change 'forall' to 'exists' in existential data constructors like this one. You did mention it, and there were several replies. I'd characterise them as

Re: forall quantifier

2003-06-05 Thread Andreas Rossberg
Ketil Z. Malde wrote: I have a function declared as: anova2 :: (Fractional c, Ord b) = [a-b] - (a-c) - [a] - [Anova1 c] where the first parameter is a list of classifiers. I could simplify it, I guess, to something like classify :: Eq b = [a-b] - [a] - [[[a]]]

Re: forall quantifier

2003-06-05 Thread Graham Klyne
I don't properly understand this either, but as it happens I was looking at this in the GHC user guide only yesterday... [[ : MkFoo :: forall a. a - (a - Bool) - Foo Nil :: Foo Notice that the type variable a in the type of MkFoo does not appear in the data type itself, which is plain

Re: forall quantifier

2003-06-05 Thread Tomasz Zielonka
On Wed, Jun 04, 2003 at 02:46:59PM +0200, [EMAIL PROTECTED] wrote: Now I want to print part of the record. What I would like to do is the following putStrLn $ concatMap show [a,c,d] !!! bang !!! So what I actually do is putStrLn $ concat [show a, show c, show d] Works, but a

RE: forall quantifier

2003-06-05 Thread Markus . Schnell
Yes, this would work, thanks. But let me extent my question: what if all the types would be in a class FakeClass which has function specialID :: a - ID and I would like to do foo $ map specialID [a,b,c,d] ? ___ Haskell mailing list [EMAIL PROTECTED]

Re: forall quantifier

2003-06-05 Thread Tomasz Zielonka
On Wed, Jun 04, 2003 at 04:43:10PM +0200, [EMAIL PROTECTED] wrote: Yes, this would work, thanks. But let me extent my question: what if all the types would be in a class FakeClass which has function specialID :: a - ID and I would like to do foo $ map specialID [a,b,c,d] ? Well, in

RE: forall quantifier

2003-06-04 Thread Markus . Schnell
Now, obviously, the problem is that fst and snd, being passed in a list, needs to be of the same type; this complicates classifying a list of type [(Int,Bool)], for instance¹. I have a similar problem. Say I have a record: data Rec = Rec { a :: Int, b :: Type1, c :: Type2, d :: Type3, ... }