Re: Original stdout inside the $(shell ...) function

On Tue, 2018-04-10 at 13:07 +0300, Basin Ilya wrote: > As you can see, the message "finding SQLFILES..." is printed to > stderr, but I want the original stdout instead. Does GNU Make make it > available as some other fd, say, "4"? Good that you got an answer; just for completeness I'll say that no

Re: Original stdout inside the $(shell ...) function

Basin, This should do what you want: SQLFILES := $(info finding SQLFILES...)$(shell cd "$(srcdir)" && find . -name "*.sql") Sam Kendall On Tue, Apr 10, 2018 at 11:08 AM Basin Ilya wrote: > Hi David. > I'll try to explain what I want better. The evaluation should print a > diagnostic message a

Re: Original stdout inside the $(shell ...) function

Thank you Sam, that's exactly what I needed. On 10.04.2018 18:12, Sam Kendall wrote: > Basin, > > This should do what you want: > > SQLFILES := $(info finding SQLFILES...)$(shell cd "$(srcdir)" && find . -name > "*.sql") > > Sam Kendall > > On Tue, Apr 10, 2018 at 11:08 AM Basin Ilya

Re: Original stdout inside the $(shell ...) function

Hi David. I'll try to explain what I want better. The evaluation should print a diagnostic message and it should be printed to a file descriptor that was the stdout of the make program when it was started. That is, when you run the make command with output redirected to /dev/null, the diagnostic

Re: Original stdout inside the $(shell ...) function

This looks like a basic shell programming issue, not a make problem at all. Try pulling this logic out of make and running it directly in the shell; if it behaves correctly there but not when plugged back into make, then you'll have a make question. This looks more like a scoping problem. Here is (