// tst.cpp
#include iostream.h
main() {
char cArr[] = {'a','b','c','\0'};
int iArr[] = {1, 2, 3};
cout cArr= cArr iArr= iArr endl;
}
// Output: cArr=abc iArr=0x2ff202f8
Q: Why is iArr 0x2ff202f8 and not '123' ?
Regards,
Nishi
- Original Message -
From: Kapoor, Nishikant X [EMAIL PROTECTED]
Q: Why is iArr 0x2ff202f8 and not '123' ?
Because for arrays,any arrays, the array variable stands for the pointer to
the first
index(index 0). char * is handled specially i.e. there is language support,
for it to be
