Anton created SPARK-12703: ----------------------------- Summary: Spark KMeans Documentation Python Api Key: SPARK-12703 URL: https://issues.apache.org/jira/browse/SPARK-12703 Project: Spark Issue Type: Documentation Components: MLlib Reporter: Anton Priority: Minor
In the documentation of Spark's Kmeans - python api: http://spark.apache.org/docs/latest/mllib-clustering.html#k-means the cost of the final result is calculated using the 'error()' function where its returning: {quote} return sqrt(sum([x**2 for x in (point - center)])) {quote} As I understand, it's wrong to use sqrt() and it should be omitted {quote} sum([x**2 for x in (point - center)]).{quote} Please refer to : https://en.wikipedia.org/wiki/K-means_clustering#Description Where you can see that the power is canceling the square. What do you think? It's minor but wasted me a few min to understand why the result isn't what I'm expecting. -- This message was sent by Atlassian JIRA (v6.3.4#6332) --------------------------------------------------------------------- To unsubscribe, e-mail: issues-unsubscr...@spark.apache.org For additional commands, e-mail: issues-h...@spark.apache.org