Xiao Li created SPARK-16803:
-------------------------------
Summary: SaveAsTable does not work when source DataFrame is built
on a Hive Table
Key: SPARK-16803
URL: https://issues.apache.org/jira/browse/SPARK-16803
Project: Spark
Issue Type: Bug
Components: SQL
Affects Versions: 2.0.0
Reporter: Xiao Li
{{noformat}}
scala> sql("create table sample.sample stored as SEQUENCEFILE as select 1 as
key, 'abc' as value")
res2: org.apache.spark.sql.DataFrame = []
scala> val df = sql("select key, value as value from sample.sample")
df: org.apache.spark.sql.DataFrame = [key: int, value: string]
scala> df.write.mode("append").saveAsTable("sample.sample")
scala> sql("select * from sample.sample").show()
+---+-----+
|key|value|
+---+-----+
| 1| abc|
| 1| abc|
+---+-----+
{{noformat}}
In Spark 1.6, it works, but Spark 2.0 does not work. The error message from
Spark 2.0 is
{{noformat}}
scala> df.write.mode("append").saveAsTable("sample.sample")
org.apache.spark.sql.AnalysisException: Saving data in MetastoreRelation
sample, sample
is not supported.;
{{noformat}}
So far, we do not plan to support it in Spark 2.0. Spark 1.6 works because it
internally uses {{insertInto}}. But, if we change it back it will break the
semantic of {{saveAsTable}} (this method uses by-name resolution instead of
using by-position resolution used by {{insertInto}}).
Instead, users should use {{insertInto}} API. We should correct the error
messages. Users can understand how to bypass it before we support it.
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