Bruce Robbins created SPARK-45896:
-------------------------------------
Summary: Expression encoding fails for Seq/Map of Option[Seq]
Key: SPARK-45896
URL: https://issues.apache.org/jira/browse/SPARK-45896
Project: Spark
Issue Type: Bug
Components: SQL
Affects Versions: 3.5.0, 3.4.1
Reporter: Bruce Robbins
The following action fails on 3.4.1, 3.5.0, and master:
{noformat}
scala> val df = Seq(Seq(Some(Seq(0)))).toDF("a")
val df = Seq(Seq(Some(Seq(0)))).toDF("a")
org.apache.spark.SparkRuntimeException: [EXPRESSION_ENCODING_FAILED] Failed to
encode a value of the expressions: mapobjects(lambdavariable(MapObject,
ObjectType(class java.lang.Object), true, -1),
mapobjects(lambdavariable(MapObject, ObjectType(class java.lang.Object), true,
-2), assertnotnull(validateexternaltype(lambdavariable(MapObject,
ObjectType(class java.lang.Object), true, -2), IntegerType, IntegerType)),
unwrapoption(ObjectType(interface scala.collection.immutable.Seq),
validateexternaltype(lambdavariable(MapObject, ObjectType(class
java.lang.Object), true, -1), ArrayType(IntegerType,false), ObjectType(class
scala.Option))), None), input[0, scala.collection.immutable.Seq, true], None)
AS value#0 to a row. SQLSTATE: 42846
...
Caused by: java.lang.RuntimeException: scala.Some is not a valid external type
for schema of array<int>
at
org.apache.spark.sql.catalyst.expressions.GeneratedClass$SpecificUnsafeProjection.MapObjects_0$(Unknown
Source)
...
{noformat}
However, it succeeds on 3.3.3:
{noformat}
scala> val df = Seq(Seq(Some(Seq(0)))).toDF("a")
df: org.apache.spark.sql.DataFrame = [a: array<array<int>>]
scala> df.collect
res0: Array[org.apache.spark.sql.Row] = Array([WrappedArray(WrappedArray(0))])
{noformat}
Map of option of sequence also fails on 3.4.1, 3.5.0, and master:
{noformat}
scala> val df = Seq(Map(0 -> Some(Seq(0)))).toDF("a")
val df = Seq(Map(0 -> Some(Seq(0)))).toDF("a")
org.apache.spark.SparkRuntimeException: [EXPRESSION_ENCODING_FAILED] Failed to
encode a value of the expressions:
externalmaptocatalyst(lambdavariable(ExternalMapToCatalyst_key,
ObjectType(class java.lang.Object), false, -1),
assertnotnull(validateexternaltype(lambdavariable(ExternalMapToCatalyst_key,
ObjectType(class java.lang.Object), false, -1), IntegerType, IntegerType)),
lambdavariable(ExternalMapToCatalyst_value, ObjectType(class java.lang.Object),
true, -2), mapobjects(lambdavariable(MapObject, ObjectType(class
java.lang.Object), true, -3),
assertnotnull(validateexternaltype(lambdavariable(MapObject, ObjectType(class
java.lang.Object), true, -3), IntegerType, IntegerType)),
unwrapoption(ObjectType(interface scala.collection.immutable.Seq),
validateexternaltype(lambdavariable(ExternalMapToCatalyst_value,
ObjectType(class java.lang.Object), true, -2), ArrayType(IntegerType,false),
ObjectType(class scala.Option))), None), input[0,
scala.collection.immutable.Map, true]) AS value#0 to a row. SQLSTATE: 42846
...
Caused by: java.lang.RuntimeException: scala.Some is not a valid external type
for schema of array<int>
at
org.apache.spark.sql.catalyst.expressions.GeneratedClass$SpecificUnsafeProjection.MapObjects_0$(Unknown
Source)
...
{noformat}
As with the first example, this succeeds on 3.3.3:
{noformat}
scala> val df = Seq(Map(0 -> Some(Seq(0)))).toDF("a")
df: org.apache.spark.sql.DataFrame = [a: map<int,array<int>>]
scala> df.collect
res0: Array[org.apache.spark.sql.Row] = Array([Map(0 -> WrappedArray(0))])
{noformat}
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