[ https://issues.apache.org/jira/browse/SPARK-17863?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel ]
Yin Huai resolved SPARK-17863. ------------------------------ Resolution: Fixed Fix Version/s: 2.1.0 2.0.2 Issue resolved by pull request 15489 [https://github.com/apache/spark/pull/15489] > SELECT distinct does not work if there is a order by clause > ----------------------------------------------------------- > > Key: SPARK-17863 > URL: https://issues.apache.org/jira/browse/SPARK-17863 > Project: Spark > Issue Type: Bug > Components: SQL > Reporter: Yin Huai > Priority: Blocker > Labels: correctness > Fix For: 2.0.2, 2.1.0 > > > {code} > select distinct struct.a, struct.b > from ( > select named_struct('a', 1, 'b', 2, 'c', 3) as struct > union all > select named_struct('a', 1, 'b', 2, 'c', 4) as struct) tmp > order by struct.a, struct.b > {code} > This query generates > {code} > +---+---+ > | a| b| > +---+---+ > | 1| 2| > | 1| 2| > +---+---+ > {code} > The plan is wrong because the analyze somehow added {{struct#21805}} to the > project list, which changes the semantic of the distinct (basically, the > query is changed to {{select distinct struct.a, struct.b, struct}} from > {{select distinct struct.a, struct.b}}). > {code} > == Parsed Logical Plan == > 'Sort ['struct.a ASC, 'struct.b ASC], true > +- 'Distinct > +- 'Project ['struct.a, 'struct.b] > +- 'SubqueryAlias tmp > +- 'Union > :- 'Project ['named_struct(a, 1, b, 2, c, 3) AS struct#21805] > : +- OneRowRelation$ > +- 'Project ['named_struct(a, 1, b, 2, c, 4) AS struct#21806] > +- OneRowRelation$ > == Analyzed Logical Plan == > a: int, b: int > Project [a#21819, b#21820] > +- Sort [struct#21805.a ASC, struct#21805.b ASC], true > +- Distinct > +- Project [struct#21805.a AS a#21819, struct#21805.b AS b#21820, > struct#21805] > +- SubqueryAlias tmp > +- Union > :- Project [named_struct(a, 1, b, 2, c, 3) AS struct#21805] > : +- OneRowRelation$ > +- Project [named_struct(a, 1, b, 2, c, 4) AS struct#21806] > +- OneRowRelation$ > == Optimized Logical Plan == > Project [a#21819, b#21820] > +- Sort [struct#21805.a ASC, struct#21805.b ASC], true > +- Aggregate [a#21819, b#21820, struct#21805], [a#21819, b#21820, > struct#21805] > +- Union > :- Project [1 AS a#21819, 2 AS b#21820, [1,2,3] AS struct#21805] > : +- OneRowRelation$ > +- Project [1 AS a#21819, 2 AS b#21820, [1,2,4] AS struct#21806] > +- OneRowRelation$ > == Physical Plan == > *Project [a#21819, b#21820] > +- *Sort [struct#21805.a ASC, struct#21805.b ASC], true, 0 > +- Exchange rangepartitioning(struct#21805.a ASC, struct#21805.b ASC, 200) > +- *HashAggregate(keys=[a#21819, b#21820, struct#21805], functions=[], > output=[a#21819, b#21820, struct#21805]) > +- Exchange hashpartitioning(a#21819, b#21820, struct#21805, 200) > +- *HashAggregate(keys=[a#21819, b#21820, struct#21805], > functions=[], output=[a#21819, b#21820, struct#21805]) > +- Union > :- *Project [1 AS a#21819, 2 AS b#21820, [1,2,3] AS > struct#21805] > : +- Scan OneRowRelation[] > +- *Project [1 AS a#21819, 2 AS b#21820, [1,2,4] AS > struct#21806] > +- Scan OneRowRelation[] > {code} > If you use the following query, you will get the correct result > {code} > select distinct struct.a, struct.b > from ( > select named_struct('a', 1, 'b', 2, 'c', 3) as struct > union all > select named_struct('a', 1, 'b', 2, 'c', 4) as struct) tmp > order by a, b > {code} -- This message was sent by Atlassian JIRA (v6.3.4#6332) --------------------------------------------------------------------- To unsubscribe, e-mail: issues-unsubscr...@spark.apache.org For additional commands, e-mail: issues-h...@spark.apache.org