I'm not quite sure which part you're asking about. To get and interact
with your example data, you could do something like:
$.getJSON('/url/to/json', function(data) {
for(var i = 0; i data.models.length; i++) {
$('#output').append('div' + data.models[i] + '/div'); // or
whatever you want
Right, 'count' doesn't have any special meaning that I know of. What are you
expecting it to be? Arrays have a special property called length, which
you could access like json.models.length, but Objects (like your json
variable), don't necessarily have this special property.
--Erik
On 8/16/07,
From: jeff w
I am new to jQuery, and have started to play with JSON,but I
need some info about how I refer to the JSON Object once it
is returned from the server. I know I can loop through the
contents of the object, and I can use json.count, but I am
really unsure about the correct
I assumed he was using $.getJSON or something similar that takes care of the
eval'ing for you.
--Erik
On 8/16/07, Michael Geary [EMAIL PROTECTED] wrote:
From: jeff w
I am new to jQuery, and have started to play with JSON,but I
need some info about how I refer to the JSON Object once
Oh, you're right, Erik, I wasn't paying close enough attention to the
related thread. Jeff, skip the eval in the code I listed if it's coming from
$.getJSON. :-)
-Mike
_
From: Erik Beeson
I assumed he was using $.getJSON or something similar that takes care of the
eval'ing for you.
Thats it! I was referring to the length as 'count'. Thats why my for
loop wasn't executing, and thats why I couldn't echo my data in the
browser.
Thanks!
So, should I treat my JSON object like a Javascript multi-dimensional
array?
On Aug 16, 10:20 am, Erik Beeson [EMAIL PROTECTED] wrote:
Yes, I am using $.getJSON. eval() is a javascript function right? so
if I want more info on that, I should look at a javascript reference??
what is console.debug()? I've seen that in a bunch of posts. I am
guessing its a way to output results. Is it a cleaner way of using
something like
Like Mike said, you don't need eval() when using $.getJSON().
That console.* stuff is part of a FireFox extension called FireBug that's
fairly standard for doing development.
--Erik
On 8/16/07, jeff w [EMAIL PROTECTED] wrote:
Yes, I am using $.getJSON. eval() is a javascript function right?
So, should I treat my JSON object like a Javascript
multi-dimensional array?
Seeing as how JavaScript doesn't *have* multi-dimensional arrays, I probably
wouldn't put it exactly that way. :-)
But you definitely have the right idea. JSON is simply a text representation
of JavaScript objects,
Jeff,
Firebug and Web Developer extensions for Firefox will become very
useful for you.
There is also a jQuery extension for Firebug debugging:
http://jquery.glyphix.com/
Good instructions on that page.
A JSON (or other Javascript) Object != a multidimensional array.
Javascript objects can be
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