There're different ways:
obj instanceof jQuery
obj && obj.constructor == jQuery
obj && obj.jquery
And any other possible attribute sniffing, 'jquery' is obviously the
safest.
--
Ariel Flesler
http://flesler.blogspot.com
On Jan 5, 7:08 pm, Eric Garside wrote:
> This sort of thing can happen a
'.hidden').hide('fast');
$obj.show('fast');
}
-Original Message-
From: jquery-en@googlegroups.com [mailto:jquery...@googlegroups.com] On
Behalf Of MorningZ
Sent: Monday, January 05, 2009 2:57 PM
To: jQuery (English)
Subject: [jQuery] Re: Test if a varia
This sort of thing can happen a lot if you're writing functions which
take multiple inputs, based on convenience. Being "in control" of your
code shouldn't be a fascist thing like you're describing, where
there's only one way in which everything can or should happen. Having
openness in parameters
I'm trying to grasp the concept of need for this check
What's a situation where you would wonder what it is? Are you not in
control of your own code or something?
On Jan 5, 3:53 pm, "Andy Matthews" wrote:
> How can I test to see if something is a jQuery object, or a normal
> JavaScript obj
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