Thanks! Unfortunately I still work in a jQuery-less environment, but
that's changing :)
cheers,
- ricardo
On Nov 22, 2:14 am, Karl Swedberg [EMAIL PROTECTED] wrote:
One very minor note: you don't need to do this:
var elm = e.target || e.srcElement;
this is fine:
var elm =
It still doesn't work. I think part of the problem is because the
children of main are added after I create the event listener.
Second solution is to check in the event listener if the target is a
child of main and if so, return. I know how to get the children of
main , but how to I check the
My mistake, it is working. The problem was my lack of understanding
about how Dialog works. main is the div from which I create a Dialog
and I didn't want the event listener to be added to the elements of
main. However main is NOT the first element of the Dialog. I the
background it is wrapped
Why dont you fire an event after the children have been loaded that
removes them?
On Nov 21, 3:07 am, [EMAIL PROTECTED]
[EMAIL PROTECTED] wrote:
My mistake, it is working. The problem was my lack of understanding
about how Dialog works. main is the div from which I create a Dialog
and I
By the way, you could use event delegation to simplify things a lot:
$(document).ready(function(){
$('body').mouseover(function(e){
var elm = e.target || e.srcElement;
if ( !$(elm).parents('.ui-dialog').length ) { //if .ui-dialog
is not an ancestor
$(elm).doStuff();
One very minor note: you don't need to do this:
var elm = e.target || e.srcElement;
this is fine:
var elm = e.target;
jQuery normalizes the target property. From the core file ...
// Fix target property, if necessary
if ( !event.target )
This might work better with filter() (untested):
$('*').filter('#main, #main *').mouseover(function() {
});
-Hector
On Thu, Nov 20, 2008 at 8:07 AM, [EMAIL PROTECTED]
[EMAIL PROTECTED] wrote:
Hi,
I want to apply a mouseover event on all elements but one and its
children. I can't use
That doesn't work, it doesn't exclude #main and its children
On 20 nov, 17:07, Hector Virgen [EMAIL PROTECTED] wrote:
This might work better with filter() (untested):
$('*').filter('#main, #main *').mouseover(function() {
});
-Hector
On Thu, Nov 20, 2008 at 8:07 AM, [EMAIL PROTECTED]
Are you sure you want to apply it to *all* elements on the page? That
sounds a bit awkward.
var main = $('#main, #main *');
$('body *').not(main).mouseover(function(){...});
On Nov 20, 2:07 pm, [EMAIL PROTECTED]
[EMAIL PROTECTED] wrote:
Hi,
I want to apply a mouseover event on all elements
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