Well its for a chat box and I want to remove old messages as new
messages come in, so that there are 20 messages being shown at any one
time, using = works perfectly if you add 1 new message because it
selects the last message ID and subtracts 20, but if you add 2
messages then the first message
Then use indexes from the parent and :lt (
http://docs.jquery.com/Selectors/lt#index)
aquaone
On Tue, Sep 1, 2009 at 04:07, Namir namiras...@hotmail.com wrote:
Well its for a chat box and I want to remove old messages as new
messages come in, so that there are 20 messages being shown at any
I tried using this $(span.message[id=+old_messages+]:lt(100)).hide
(slide, {direction: up}, 2000); but it doesnt seem to be working
correctly
On Sep 1, 7:07 pm, aquaone aqua...@gmail.com wrote:
Then use indexes from the parent and :lt
(http://docs.jquery.com/Selectors/lt#index)
aquaone
wouldnt work, even if I set the index to count the number of messages
and subtract 20 and index those as sometimes there may be missing ID's
as they may have been deleted.
On Sep 1, 9:59 pm, James james.gp@gmail.com wrote:
Try using just:
$(span.message:lt(100))
If you want to remove
It doesn't matter if they're missing IDs. You don't need the IDs.
(Also, IDs cannot begin with a number. It's not valid.)
All you need to know is how many new messages you received on your
latest update (to determine how many old ones to remove), and your
maximum number of messages to display at
Try using just:
$(span.message:lt(100))
If you want to remove elements that are on the bottom, you may want to
use gt() instead of lt().
For example, suppose your code looks like:
span class=message id=msg5test/span // index 0
span class=message id=msg4test/span // index 1
span class=message
Thats a very smart way of doing it. Thanks a lot. Also why is it
invalid to start an ID as a number? I'm not receiving any errors by
doing it. Should I instead set a custom attribute called msg_id and
use that?
On Sep 1, 10:21 pm, James james.gp@gmail.com wrote:
It doesn't matter if they're
*http://www.w3.org/TR/html4/types.html#type-id
ID* and *NAME* tokens must begin with a letter ([A-Za-z]) and may be
followed by any number of letters, digits ([0-9]), hyphens (-),
underscores (_), colons (:), and periods (.).
On Tue, Sep 1, 2009 at 14:44, Namir namiras...@hotmail.com wrote:
, August 31, 2009 2:33 PM
To: jQuery (English)
Subject: [jQuery] Re: jQuery select where attribute ID less than
Still how would I do it with an each? I'd still need to select all the
ones with an attribute of less than x, and it would be stupid to loop
it from 1 to whatever as x can reach
id will be a string. AFAIK there's no built-in to parse it as a number and
compare. you'd either have to .each() it or find another means of
accomplishing what you are trying to do.
aquaone
On Mon, Aug 31, 2009 at 13:50, Namir namiras...@hotmail.com wrote:
How can I do a less than in a
Still how would I do it with an each? I'd still need to select all the
ones with an attribute of less than x, and it would be stupid to loop
it from 1 to whatever as x can reach thousands. Do you have any other
suggestions as to how I could do this?
On Aug 31, 9:58 pm, aquaone aqua...@gmail.com
(English)
Subject: [jQuery] Re: jQuery select where attribute ID less than
Still how would I do it with an each? I'd still need to select all the
ones with an attribute of less than x, and it would be stupid to loop
it from 1 to whatever as x can reach thousands. Do you have any other
suggestions
...@googlegroups.com] On
Behalf Of Namir
Sent: Monday, August 31, 2009 2:33 PM
To: jQuery (English)
Subject: [jQuery] Re: jQuery select where attribute ID less than
Still how would I do it with an each? I'd still need to select all the
ones with an attribute of less than x, and it would be stupid to loop
Can you give us a hint what your DOM elements look like? For example, are
these ID attributes in ascending order in the DOM? That would allow you to
use a very fast binary search. If they are in an undetermined order then
you're pretty much stuck with looping through them - but with thousands of
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