On May 17, 7:14 am, kali wrote:
> On May 6, 12:18 am, Karl Swedberg wrote:
>
>
>
> > On May 6, 2009, at 12:05 AM,kaliwrote:
>
> > > On May 5, 10:05 pm, mkmanning wrote:
> > >> Accessing the elements by index returns the element itself. To call
> > >> jQuery methods you'd need to do this:
> >
On May 17, 7:14 am, kali wrote:
> On May 6, 12:18 am, Karl Swedberg wrote:
>
>
>
> > On May 6, 2009, at 12:05 AM,kaliwrote:
>
> > > On May 5, 10:05 pm, mkmanning wrote:
> > >> Accessing the elements by index returns the element itself. To call
> > >> jQuery methods you'd need to do this:
> >
On May 6, 12:18 am, Karl Swedberg wrote:
> On May 6, 2009, at 12:05 AM, kali wrote:
>
> > On May 5, 10:05 pm, mkmanning wrote:
> >> Accessing the elements by index returns the element itself. To call
> >> jQuery methods you'd need to do this:
> >> divs = $('div');
> >> div2 = divs[2];
>
> > TH
On May 6, 2009, at 12:05 AM, kali wrote:
On May 5, 10:05 pm, mkmanning wrote:
Accessing the elements by index returns the element itself. To call
jQuery methods you'd need to do this:
divs = $('div');
div2 = divs[2];
THIS is what I did
div2 = divs[2] --> is IGNORED
It's NOT ig
On May 5, 10:05 pm, mkmanning wrote:
> Accessing the elements by index returns the element itself. To call
> jQuery methods you'd need to do this:
> divs = $('div');
> div2 = divs[2];
THIS is what I did
div2 = divs[2] --> is IGNORED
pls run http://www.mayacove.com/dev/jquery/arr
Accessing the elements by index returns the element itself. To call
jQuery methods you'd need to do this:
divs = $('div');
div2 = divs[2];
$(div2).addClass('red');
or alternately you could do:
div2 = $(divs[2]);
div2.addClass('red');
you can also use .eq(#):
div2 = divs.eq(2)
div2.addClass('red
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