[jQuery] Re: the best way to handle a group of div elements

2009-06-30 Thread Antonio
ok.. can I see the corresponding HTML code where is defined iti and skipped ? On 29 Giu, 21:38, Mean Mike mcgra...@gmail.com wrote: thats odd I use that syntax all the time  like this     $(#iti, #skipped).sortable({         connectWith: ['.connectedSortable'],         receive: function(e,

[jQuery] Re: the best way to handle a group of div elements

2009-06-30 Thread Mean Mike
sure here ya go I took out all the smarty div class=transfer label for=itiIn This Issue/label ul id=iti class=connectedSortable sortable li class=hidden/li li id=iti_01 li content for iti goes here/li /ul label

[jQuery] Re: the best way to handle a group of div elements

2009-06-29 Thread MorningZ
The selector should be a *string*, to which $(.nc1).removeClass('hidden') is not... $(.nc1).removeClass('hidden') should work On Jun 29, 11:58 am, Antonio antonio.pie...@gmail.com wrote: Hi folk, In HTML code I have this situation: div id=nam1 class='nc1 nc2 nc3 hidden'/div div

[jQuery] Re: the best way to handle a group of div elements

2009-06-29 Thread Mean Mike
your missing quotes $('.nc1').removeClass('hidden') On Jun 29, 11:58 am, Antonio antonio.pie...@gmail.com wrote: Hi folk, In HTML code I have this situation: div id=nam1 class='nc1 nc2 nc3 hidden'/div div id=nam2 class='nc1 nc2 nc3 hidden'/div I would like to remove hidden to class

[jQuery] Re: the best way to handle a group of div elements

2009-06-29 Thread Antonio
and if I have the following html code div id=nam1 class='nc1 nc2 nc3 hidden'/div div id=nam2 class='nc1 nc2 nc3 hidden'/div div id=nam3 class='nc1 xxx hidden'/div div id=nam4 class='nc1 xxx hidden'/div and I would like to handle only div elements with class values starting with nc1 nc2 how can

[jQuery] Re: the best way to handle a group of div elements

2009-06-29 Thread Mean Mike
you need the . again like this var div_elements = $('.nc1 .nc2'); On Jun 29, 1:37 pm, Antonio antonio.pie...@gmail.com wrote: and if I have the following html code div id=nam1 class='nc1 nc2 nc3 hidden'/div div id=nam2 class='nc1 nc2 nc3 hidden'/div div id=nam3 class='nc1 xxx hidden'/div

[jQuery] Re: the best way to handle a group of div elements

2009-06-29 Thread Antonio
As you can see at this page: http://webcms.ba.infn.it/~pierro/GUIcondDb/CondDBMonitoring/test.html# var div_elements = $('.nc1 .nc2'); doesn't work Antonio On 29 Giu, 19:37, Antonio antonio.pie...@gmail.com wrote: and if I have the following html code div id=nam1 class='nc1 nc2 nc3

[jQuery] Re: the best way to handle a group of div elements

2009-06-29 Thread Antonio
also var div_elements = $('.nc1, nc2') doesn't work because it works like nc1 OR nc2 the solution is to write var div_elements = $('.nc1.nc2') i.e. .nc1.nc2 tied without empty space.. thanks Antonio On 29 Giu, 21:01, Mean Mike mcgra...@gmail.com wrote: my bad you need a comma separator as

[jQuery] Re: the best way to handle a group of div elements

2009-06-29 Thread Mean Mike
my bad you need a comma separator as well var div_elements = $('.nc1, .nc2'); On Jun 29, 2:55 pm, Antonio antonio.pie...@gmail.com wrote: As you can see at this page:http://webcms.ba.infn.it/~pierro/GUIcondDb/CondDBMonitoring/test.html# var div_elements = $('.nc1 .nc2'); doesn't work

[jQuery] Re: the best way to handle a group of div elements

2009-06-29 Thread Mean Mike
thats odd I use that syntax all the time like this $(#iti, #skipped).sortable({ connectWith: ['.connectedSortable'], receive: function(e, ui) { var item_id = $(ui.item).attr('id'); $(ui.item).attr('id', $(this).attr('id') + item_id.substr