Re: [julia-users] Updated performance tips?

2016-11-23 Thread Harish Kumar
2016 at 1:12:26 PM UTC-6, Harish Kumar wrote: > > I found the cause for this ... When i run julia 0.3.2 or 0.5 as > standalone (mix model) it uses all the available cores from my server, so > it was fast. > > Fitting a linear mixed effects model only uses multiple threads for the &

Re: [julia-users] Updated performance tips?

2016-11-22 Thread Harish Kumar
how can i force Pyjulia/python to use available cores from my server? Regards, Harish On Sat, Nov 19, 2016 at 8:32 PM, Mauro <mauro...@runbox.com> wrote: > On Sat, 2016-11-19 at 20:48, Harish Kumar <harish.kuma...@gmail.com> > wrote: > > Thank you. I agree on python..

Re: [julia-users] Updated performance tips?

2016-11-19 Thread Harish Kumar
PM, Mauro <mauro...@runbox.com> wrote: > On Sat, 2016-11-19 at 18:36, Harish Kumar <harish.kuma...@gmail.com> > wrote: > > Will it support Python 3.4 ? I am calling this from pyjulia interface > > https://github.com/JuliaPy/pyjulia says that it is tested against 3.5,

Re: [julia-users] Updated performance tips?

2016-11-19 Thread Harish Kumar
Will it support Python 3.4 ? I am calling this from pyjulia interface On Nov 19, 2016 4:58 PM, "Mauro" <mauro...@runbox.com> wrote: > Julia 0.3.12, that's a stone-age version of Julia. You should move to 0.5! > > On Sat, 2016-11-19 at 16:42, Harish Kumar <haris

Re: [julia-users] Updated performance tips?

2016-11-19 Thread Harish Kumar
I am using Version 0.3.12 calling from python (pyjulia). I do LME fit with 2.8 M rows and 60-70 Variables. It is taking 2 hours just to model (+ data transfer time). Any tips? using MixedModels modelREML = lmm({formula}, dataset) reml!(modelREML,true) lmeModel =

[julia-users] Re: Calling Julia code from Python

2016-11-02 Thread Harish Kumar
Use pyjulia package. Convert your data set to list of list and pass to Julia On Wednesday, November 2, 2016 at 1:43:27 PM UTC-5, Alexei Serdiuk wrote: > > Hi, > > I'm new to Julia and, unfortunately, I'm almost zero to Python. > I need to call Julia code from Python. This code must do some

[julia-users] Call Julia from Pyspark

2016-11-02 Thread Harish Kumar
I have a RDD with 10K columns and 70 million rows, 70 MM rows will be grouped into 2000-3000 groups based on a key attribute. I followed below steps 1. Julia and Pyspark linked using pyjulia package 2. 70 MM rd is groupByKey def juliaCall(x): <> j = julia.Julia() jcode