Hi!
Probably a quite basic question but was wondering if someone knows a quick
way to get the average of theh positive elements of a matrix, eg, If I have
an m*n matrix and want to get the average for each m so have m*1 but only
want to work with non-zero elements and ignore the zero elements
You mean quicker as in faster or as in easier? Using indexing is probably
easiest but not fastest:
julia M = randn(5,5)
5x5 Array{Float64,2}:
-1.51134 1.2331-0.186083 0.412282 -1.13114
-0.0411132 0.124684 0.377426 0.622427 -0.278162
0.788182 -0.834092 1.095061.45196
Heh... neither did I... I gave you code for column sums! Should be easy
enough to convert...
On Tue, Jul 28, 2015 at 12:05 PM, Stefan Karpinski ste...@karpinski.org
wrote:
Oh, didn't catch that you wanted row sums, but yeah, same basic idea.
On Tue, Jul 28, 2015 at 12:03 PM, Tom Breloff
Oh, didn't catch that you wanted row sums, but yeah, same basic idea.
On Tue, Jul 28, 2015 at 12:03 PM, Tom Breloff t...@breloff.com wrote:
I would just write the loop explicitly:
julia function meanpositives(mat::Matrix)
nc = size(mat,2)
sums = zeros(nc)
I would just write the loop explicitly:
julia function meanpositives(mat::Matrix)
nc = size(mat,2)
sums = zeros(nc)
counts = zeros(nc)
for c in 1:nc
for r in 1:size(mat,1)
v = mat[r,c]
if v 0
Thanks Stefan and Tom, that's really helpful! Stefan, I meant quicker as
in faster.
Thanks a lot!
On Tuesday, July 28, 2015 at 5:06:00 PM UTC+1, Stefan Karpinski wrote:
Oh, didn't catch that you wanted row sums, but yeah, same basic idea.
On Tue, Jul 28, 2015 at 12:03 PM, Tom Breloff
