[julia-users] Re: Trouble deducing type parameter with inner constructor

2014-08-26 Thread Magnus Lie Hetland
OK, this works: immutable A{N} x::NTuple{N, Int} y::Int A(x, y) = new(x, y + 1) end A{N}(x::NTuple{N, Int}, y::Int) = A{N}(x, y) But why is this necessary? (Adding type decl. to the internal constructor doesn't seem to do anything useful.) And why is it not necessary if I

[julia-users] Re: Trouble deducing type parameter with inner constructor

2014-08-26 Thread Tobias Knopp
I don't really know if this is a bug or if there is some good technical reason for this. What seems to happen is that the definition A(x, y) = new(x, y + 1) removes the default constructor. You can see this by typing A on the REPL (or methods(A)) Am Dienstag, 26. August 2014 09:14:10 UTC+2

[julia-users] Re: Trouble deducing type parameter with inner constructor

2014-08-26 Thread Magnus Lie Hetland
Hm, yes. Is this somehow related to the default constructor stuff added in 0.3 (linked to issues #4026 https://github.com/JuliaLang/julia/issues/4026 and #7071 https://github.com/JuliaLang/julia/issues/7071)? Not that I see exactly how they'd be related, except that they're linked to the same

[julia-users] Re: Trouble deducing type parameter with inner constructor

2014-08-26 Thread Tobias Knopp
Magnus, Please feel free to file a new issue. Even if it is intentional it might have to be better documented. Cheers, Tobi Am Dienstag, 26. August 2014 10:41:30 UTC+2 schrieb Magnus Lie Hetland: Hm, yes. Is this somehow related to the default constructor stuff added in 0.3 (linked to

[julia-users] Re: Trouble deducing type parameter with inner constructor

2014-08-26 Thread Magnus Lie Hetland
Done https://github.com/JuliaLang/julia/issues/8135.