Re: [julia-users] Embedding Julia in C++ - Determining returned array types

2016-10-19 Thread Isaiah Norton
e.g. http://half.sourceforge.net/ But if you aren't sure you need to support this, then just throw an error (Float16 is relatively new and AFAICT only useful in specialized applications because of the precision limit, which is why support is rare) If you are sure you (a) need it but (b) only

Re: [julia-users] Embedding Julia in C++ - Determining returned array types

2016-10-19 Thread Stefan Karpinski
You can pull the significant bits and the exponent values out of a Float16 and then use those to compute the value as a Float32: https://en.wikipedia.org/wiki/Half-precision_floating-point_format On Wed, Oct 19, 2016 at 1:00 PM, Yichao Yu wrote: > > > On Wed, Oct 19, 2016 at

Re: [julia-users] Embedding Julia in C++ - Determining returned array types

2016-10-19 Thread Yichao Yu
On Wed, Oct 19, 2016 at 12:54 PM, Kyle Kotowick wrote: > Aha, that fixed it! > > I'm running into one issue though. What do I do with the data when it's a > "Float16" type? C++ has no way to represent a 16-bit float, so I'm having > difficulty converting it to a regular 32-bit

Re: [julia-users] Embedding Julia in C++ - Determining returned array types

2016-10-19 Thread Kyle Kotowick
Aha, that fixed it! I'm running into one issue though. What do I do with the data when it's a "Float16" type? C++ has no way to represent a 16-bit float, so I'm having difficulty converting it to a regular 32-bit float. jl_value_t *ret = jl_eval_string(code_string); jl_array_t *ret_array =

Re: [julia-users] Embedding Julia in C++ - Determining returned array types

2016-10-18 Thread Yichao Yu
On Tue, Oct 18, 2016 at 8:57 PM, Isaiah Norton wrote: > The issue here is that `jl_array_eltype` is already returning a type. > > `jl_typeis(v, t)` becomes `jl_typeof(v) == t`, so your checks become: > > jl_typeof(array_type) == jl_int64_type > > But > >

Re: [julia-users] Embedding Julia in C++ - Determining returned array types

2016-10-18 Thread Isaiah Norton
The issue here is that `jl_array_eltype` is already returning a type. `jl_typeis(v, t)` becomes `jl_typeof(v) == t`, so your checks become: jl_typeof(array_type) == jl_int64_type But jl_typeof(array_type) -> DataType Instead, either do the equality check directly: array_type ==

Re: [julia-users] Embedding Julia in C++ - Determining returned array types

2016-10-18 Thread Kyle Kotowick
I apologize for the formatting, that should be: jl_value_t *ret = jl_eval_string(code_string); void* array_type = jl_array_eltype(ret); jl_array_t *ret_array = (jl_array_t*)ret; if (jl_typeis(array_type, jl_int64_type)) { long *data = (long*) jl_array_data(ret_array); } else if

Re: [julia-users] Embedding Julia in C++ - Determining returned array types

2016-10-15 Thread Bart Janssens
In addition to this, CxxWrap.jl has some additional convenience classes to work with Julia arrays from C++, see https://github.com/JuliaInterop/CxxWrap.jl#working-with-arrays Cheers, Bart On Sat, Oct 15, 2016 at 2:45 AM Isaiah Norton wrote: > On Fri, Oct 14, 2016 at

Re: [julia-users] Embedding Julia in C++ - Determining returned array types

2016-10-14 Thread Isaiah Norton
On Fri, Oct 14, 2016 at 2:28 PM, Kyle Kotowick wrote: > > > After determining that an array was returned, how would you determine what > the inner type of the array is (i.e. the type of the objects it contains)? > `jl_array_eltype` > > And furthermore, if it returns an array