Am 13.11.2013 22:49, schrieb Martin:
On 13/11/2013 20:40, GREP wrote:
Hi
I could not get the breakpoints to work, I googled a lot, tried all the
suggestions
unsuccessfully.
After a full day of trial I ended up that now the project does not show
anything in the Debugger output window.
I have
Am 13.11.2013 21:40, schrieb GREP:
Hi
I could not get the breakpoints to work, I googled a lot, tried all the
suggestions
unsuccessfully.
Did you find this bug report
http://bugs.freepascal.org/view.php?id=21061 on your search? (and also
the related ones)
Regards,
Sven
--
On Wed, Nov 13, 2013 at 11:17:59PM +0100, Bart wrote:
On 11/13/13, Mattias Gaertner nc-gaert...@netcologne.de wrote:
Check your short cuts in your system settings. They take precedence
over any normal application like the IDE.
On my Fedora 18 / KDE Ctrl+F9 does something weird to the
On Thu, 14 Nov 2013 07:19:56 +0100
Jürgen Hestermann juergen.hesterm...@gmx.de wrote:
Am 2013-11-13 19:42, schrieb Reimar Grabowski:
1 julian year = 365.25 days of 86400 SI seconds each.
Of course there are lots of other definitions for year but if FPC uses the
julian one the value is
On Thu, 14 Nov 2013 07:56:16 +0100
Patrick Chevalley p...@ap-i.net wrote:
All this efforts are to bypass the problem with the calendar year (the
one you mention) because it is sometime 365 and sometime 366 days. This
is a totally unacceptable definition when you need an homogeneous time
On Wed, 13 Nov 2013 20:34:36 +0100
John Landmesser joh...@online.de wrote:
What about Databases like mysql, Oracle, Firebird. I'm shure they have
such a function.
For MySQL:
DATEDIFF(expr1,expr2)
DATEDIFF() returns expr1 – expr2 expressed as a value in days from one
date to the other. expr1
El 14/11/2013 7:56, Patrick Chevalley escribió:
All this efforts are to bypass the problem with the calendar year (the
one you mention) because it is sometime 365 and sometime 366 days. This
is a totally unacceptable definition when you need an homogeneous time
scale.
Hello,
I was following
On 14.11.2013 10:50, Reimar Grabowski wrote:
For MySQL:
DATEDIFF(expr1,expr2)
DATEDIFF() returns expr1 – expr2 expressed as a value in days from one
date to the other. expr1 and expr2 are date or date-and-time
expressions. Only the date parts of the values are used in the
calculation.
:)
R.
On 11/14/2013 4:41 AM, Reimar Grabowski wrote:
On Thu, 14 Nov 2013 07:19:56 +0100
Jürgen Hestermann juergen.hesterm...@gmx.de wrote:
Am 2013-11-13 19:42, schrieb Reimar Grabowski:
1 julian year = 365.25 days of 86400 SI seconds each.
Of course there are lots of other definitions for year
On 11/14/2013 4:50 AM, Reimar Grabowski wrote:
On Wed, 13 Nov 2013 20:34:36 +0100
John Landmesser joh...@online.de wrote:
What about Databases like mysql, Oracle, Firebird. I'm shure they have
such a function.
For MySQL:
DATEDIFF(expr1,expr2)
DATEDIFF() returns expr1 – expr2 expressed as a
On Thu, 14 Nov 2013 13:48:46 +0100
John Landmesser joh...@online.de wrote:
[...]
Our function delivers the age of a person in years, months, days.
What is your diff between 31th Jan and 30 March 2013?
Mattias
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On 11/14/2013 7:25 AM, José Mejuto wrote:
Maybe I'm completly wrong ?
you are completely right, IMHO... one simply needs to choose their desired base
and level of error that is acceptable for their task's needs...
the initial problem arose because there's no easy way to calc the desired
On 14.11.2013 14:16, Mattias Gaertner wrote:
On Thu, 14 Nov 2013 13:48:46 +0100
John Landmesser joh...@online.de wrote:
[...]
Our function delivers the age of a person in years, months, days.
What is your diff between 31th Jan and 30 March 2013?
Mattias
--
Frankly, this list from time to time ...
Em 14-11-2013 11:10, John Landmesser escreveu:
On 14.11.2013 14:16, Mattias Gaertner wrote:
On Thu, 14 Nov 2013 13:48:46 +0100
John Landmesser joh...@online.de wrote:
[...]
Our function delivers the age of a person in years, months, days.
What is
On 11/14/2013 03:46 PM, Frederic Da Vitoria wrote:
.. and where are we now??
Right in the middle of a very interesting discussion :-)
-1
-Michael
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Lazarus@lists.lazarus.freepascal.org
On 11/14/2013 8:16 AM, Mattias Gaertner wrote:
On Thu, 14 Nov 2013 13:48:46 +0100
John Landmesser joh...@online.de wrote:
[...]
Our function delivers the age of a person in years, months, days.
What is your diff between 31th Jan and 30 March 2013?
the one i am currently testing returns
John Landmesser schrieb:
Hihi, i asked a question about a DateDiff function for FreePascal,
because i wanted to know: how many years, month, days left to work in
Office until my pension begins on 01.08.2018.
What do you consider as *one* year, month etc., fixed (average) values
or calender
2013/11/14 Michael Schnell mschn...@lumino.de
On 11/14/2013 03:46 PM, Frederic Da Vitoria wrote:
.. and where are we now??
Right in the middle of a very interesting discussion :-)
-1
Well, everyone is entitled to his opinions, right, else we would all be
doing C :-)
--
Frederic
2013/11/14 John Landmesser joh...@online.de
Hihi, i asked a question about a DateDiff function for FreePascal, because
i wanted to know: how many years, month, days left to work in Office until
my pension begins on 01.08.2018.
.. and where are we now??
Right in the middle of a very
On 11/14/13, waldo kitty wkitt...@windstream.net wrote:
you are completely right, IMHO... one simply needs to choose their desired
base
and level of error that is acceptable for their task's needs...
It's all about definition.
For me I would think that given today is the last day of a given
Am 2013-11-14 07:56, schrieb Patrick Chevalley:
So the difference between 2007-01-01 12:00 and 2008-01-01 12:00 ist *not*
one year?
No, the base definition of the year is not a digit change,
but the time it take to the Earth to return at the same point of its orbit
around the Sun.
Well,
On 11/14/2013 12:26 PM, Bart wrote:
On 11/14/13, waldo kitty wkitt...@windstream.net wrote:
you are completely right, IMHO... one simply needs to choose their desired
base and level of error that is acceptable for their task's needs...
It's all about definition.
right... that's what i
On 11/14/2013 12:48 PM, Jürgen Hestermann wrote:
Am 2013-11-14 07:56, schrieb Patrick Chevalley:
So the difference between 2007-01-01 12:00 and 2008-01-01 12:00 ist
*not* one year?
No, the base definition of the year is not a digit change,
but the time it take to the Earth to return at
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