Thank you!
On Wed, Dec 6, 2017 at 12:12 PM, vitalije wrote:
> You can use:
> c.getNodeFileName(p)
>
>
> to get the full path.
> Vitalije
>
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You can use:
c.getNodeFileName(p)
to get the full path.
Vitalije
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To
if current node is
@auto /a/b/c.txt
anyAtFileNodeName() returns /a/b/c.txt
if current node is
@path a
@path b
@auto c.txt
the return is c.txt
Does Leo have a command for getting the fully qualified name,
or do I need to ascend the tree?
Thanks,
Kent
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