On Wed, Nov 11, 2009 at 12:35 AM, aw anth...@whitford.com wrote:
I need to create a snippet sequence that looks something like this:
a href=next
span class=namename/span
span class=commentdescription/span
span class=arrow/
/a
The anchor needs to be generated using SHtml.link,
You might need to surround the kids = ... function with parenthesis.
-
David Pollakfeeder.of.the.be...@gmail.com wrote:
On Wed, Nov 11, 2009 at 12:35 AM, aw anth...@whitford.com wrote:
I need to create a snippet sequence that looks something like this:
a
OK, your suggestion definitely makes the snippet code more readable,
but I fear I didn't make my point clear because the snippet code still
is highly coupled with the view layout.
Imagine that I want to change my view from this:
a href=next
span class=namename/span
span
You can do a recursive bind, but you must make it explicit:
def mySnippet(xhtml: NodeSeq): NodeSeq = {
def doBind(xhtml: NodeSeq): NodeSeq =
bind(b, xhtml,
link - { (kids: NodeSeq) = SHtml.link(next, () =
clicked(b), doBind(kids)) },
name - the name,
On Wed, Nov 11, 2009 at 11:21 AM, aw anth...@whitford.com wrote:
OK, your suggestion definitely makes the snippet code more readable,
but I fear I didn't make my point clear because the snippet code still
is highly coupled with the view layout.
If this was a MVC type framework, I think
I didn't see Tim's blog post, but another option is to bind in two passes.
First bind the outer level: b1:link should become an SHtml.link, preserving the
same set of child elements. So here use a NodeSeq function: kids =
SHtml.link(..., kids). Then pass the resulting NodeSeq to a bind
