So that means if we follow a right to left approach for establishing HTLC
i.e. from B to C first then A to B, is there a chance? But I guess that's
doesn't sound logical. Also the point raised by you is valid. B can never
be punished if it is not possessing the secret at the point of
establishment
> Why do we need another HTLC to be established from B to A ?
We don't. This wasn't what I was saying. The atomic swap example was just
to show that your idea does exist in a different context. An atomic swap
can be viewed as a payment A -> B -> A where B switches the currency.
> Pardon me if I a
Can you send the draft on fair atomic swap? Also the scenario stated in the
pdf you have shared is based on exchange of asset. But here I am not trying
to work on different ledger A to B and B to A. Here it deals with just
simple transfer of funds from A to B. So whatever HTLC A establishes with
B,
If you can atomically set up both those penalties atomically then that
would be a big breakthrough. It looks impossible. The problem is one will
be set up before the other and it is only fair if both are set up at the
same time.
LL
On Fri, Mar 6, 2020 at 5:34 PM Subhra Mazumdar <
subhra.mazumdar1
But wont the decision of penalty be based on what incoming contract expects
from a node ? Suppose there is a contract between A and B and then B and C,
where A wants to transfer money to C. So if it is the case that A impose
penalty on B using its local HTLC, won't B put the same clause on C as wel
Hi Subhra,
Afaik, the only problem is the one you identified, it doesn't work across
multiple hops but only for the final hop. This penalty idea is the basis
for doing atomc swaps fairly:
https://coblox.tech/docs/financial_crypto19.pdf
LL
On Fri, Mar 6, 2020 at 4:58 PM Subhra Mazumdar <
subhra.ma
Hi,
I was reading the paper by Poon and Dryja on Bitcoin Lightning
Network and was going through the construction of HTLC. Suppose 2 parties A
and B have a channel with each party locking 0.5 BTC. Suppose A wants to
transfer 0.1 BTC to B contingent to the knowledge of R : H=h(R) produced
with
