karol wrote
Hi! Sometimes I want my hairpin run to the end of the piece (last bar
line).
Attempt 1:
{
\override Hairpin #'to-barline = ##f
c'1~ \
c'1 \! \bar |.
}
nearly - add an empty chord like:
{
\override Hairpin.to-barline = ##f
c'1 \ c'1 ** \! \bar ||
}
this draws
{
\override Hairpin.to-barline = ##f
c'1 \ c'1 \! \bar ||
}
this draws the hairpin to the bar line though there are error messages.
Yes... using s1*0 also gives error messages.
This is really frustrating...
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lilypond-user mailing list
- Original Message -
From: Karol Majewski karo...@wp.pl
To: Eluze elu...@gmail.com
Cc: lilypond-user lilypond-user@gnu.org
Sent: Sunday, January 26, 2014 1:58 PM
Subject: Re: Hairpin to the last bar line
{
\override Hairpin.to-barline = ##f
c'1 \ c'1 \! \bar ||
}
this draws
Well, as I said, it's not clear on which beat you have to put \! here to get
the proper length of hairpin.
You could do:
{
c'1~ \
c'1 { s4*3 s4 \! } \bar |.
}
or
{
c'1~ \
c'1 { s4*3 s8 s8 \! } \bar |.
}
or
{
c'1~ \
c'1 { s4*3 s16*3 s16 \! } \bar |.
}
etc... but none of
karol wrote
etc... but none of them produces perfect output.
Inserting null event like or s1*0 produces the proper lengh of hairpin,
but gives those nasty errors...
the message I get is:
programming error: bounds of this piece aren't breakable.
what does this mean?
did you search for the
One thing I noticed is that when Hairpin.to-barline is set to ##t then there
are no errors:
{
\override Hairpin.to-barline = ##t
c'1 \ c'1 \! \bar ||
}
The same thing happens with DynamicTextSpanner. If you set \override
DynamicTextSpanner.to-barline = ##t then everything is fine:
{
On Sun, Jan 26, 2014 at 12:23:10PM +0100, Karol Majewski wrote:
Hi! Sometimes I want my hairpin run to the end of the piece (last bar line).
Attempt 1:
{
\override Hairpin #'to-barline = ##f
c'1~ \
c'1 \! \bar |.
}
Why do you set Hairpin #'to-barline = ##f if you want the
Paul Scott-4 wrote
On Sun, Jan 26, 2014 at 12:23:10PM +0100, Karol Majewski wrote:
Hi! Sometimes I want my hairpin run to the end of the piece (last bar
line).
Attempt 1:
{
\override Hairpin #'to-barline = ##f
c'1~ \
c'1 \! \bar |.
}
Why do you set Hairpin #'to-barline =
