But, to my surprise when I delete items from initialList, tempList
get the items deleted too. I can put the initial list content to a
field and extract them later after calculation. Is there a better
way to deal with this?
Yes:
newlist = duplicate(oldlist)
That will make a copy of the
tempList = initialList.duplicate()
^^^
HTH,
-Sean.
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What you're finding out is that lists are passed by reference, so when you
do tempList=initialList all you are really doing is making an additional
pointer to the same list.
This can be very helpful, or very problematic, depending on what you're
trying to accomplish! :)
But you want to
I believe that when you assign a list to variable X, that X is a reference
(or pointer) to the original list. (Unlike other situations like a number
or a string where a copy of the value is stored in X.) When you change
something via the reference, the original is changed as well. Lingo