I'd like to delete some items during a calculation on a list. But, I want
it intact after all the calculation.
So, I thought I save it to a temporary list and put it back when done.
tempList = initialList
...
all the deleteAt on initialList
...
initialList = tempList -- to get it back so I
But, to my surprise when I delete items from initialList, tempList
get the items deleted too. I can put the initial list content to a
field and extract them later after calculation. Is there a better
way to deal with this?
Yes:
newlist = duplicate(oldlist)
That will make a copy of the
tempList = initialList.duplicate()
^^^
HTH,
-Sean.
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What you're finding out is that lists are passed by reference, so when you
do tempList=initialList all you are really doing is making an additional
pointer to the same list.
This can be very helpful, or very problematic, depending on what you're
trying to accomplish! :)
But you want to
]
Sent: Wednesday, February 20, 2002 7:24 PM
Subject: lingo-l a simple list question!
I'd like to delete some items during a calculation on a list. But, I want
it intact after all the calculation.
So, I thought I save it to a temporary list and put it back when done.
tempList = initialList
