Thanks everyone, for the lively timeout answers...all very interesting
and much appreciated!
- Michael M.
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Flash has grown leaps and bounds where Director gets some
additions that aren't even needed (Real media??!?)
I _really_ don't want to be one of those troll naysayers --
hell I feed my family from ONLY director development -- but
I've got to start facing facts that there are 1000 flash
I _really_ don't want to be one of those troll naysayers --
You've got concerns based on your experience so nobody should keep you from them,
don't drop 'em, keep sharing them. I'll say from the inside that I feel confident that
Director is on an upswing in a number of ways. JHT coming back
Hi all...
It's strange: I can't seem to access items in the plain old linear list
of the timeoutlist.
put the timeoutlist
-- [timeOut(wiper)]
g = timeout( QUOTE wiper QUOTE )
put (the timeoutlist).getPos(g)
-- 0
If ((the timeoutlist).getPos(g)) 0) then -- doesn't work either
Somehow,
I figured out a workaround to my previous email:
repeat with i = 1 to (the timeoutlist).count
-- here the timeoutlist is [timeOut(wiper)]
theItem = string(the timeoutlist[i])
if theItem contains wiper then
(the
On 12/11/03 3:15 PM, Mendelsohn, Michael [EMAIL PROTECTED]
spewed forth:
put the timeoutlist
-- [timeOut(wiper)]
g = timeout( QUOTE wiper QUOTE )
put (the timeoutlist).getPos(g)
-- 0
You figured it out, but just to sum up -- g would equal timeOut(wiper)
which is a string, and
Hi Michael,
put the timeoutlist
-- [timeOut(wiper)]
g = timeout( QUOTE wiper QUOTE )
put (the timeoutlist).getPos(g)
-- 0
If ((the timeoutlist).getPos(g)) 0) then -- doesn't work either
Somehow, some way, I should get 1. What gives?
Put the timeoutlist[1] works, but I need
Thanks, Karina. Great insight.
- MM
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with programming
It's strange: I can't seem to access items in the plain old linear list
of the timeoutlist.
put the timeoutlist
-- [timeOut(wiper)]
g = timeout( QUOTE wiper QUOTE )
put (the timeoutlist).getPos(g)
-- 0
If ((the timeoutlist).getPos(g)) 0) then -- doesn't work either
Somehow, some way, I
At 15:29 Uhr -0500 11.12.2003, Mendelsohn, Michael wrote:
I figured out a workaround to my previous email:
repeat with i = 1 to (the timeoutlist).count
-- here the timeoutlist is [timeOut(wiper)]
theItem = string(the timeoutlist[i])
if
...and I've been thinking, it seems difficult at best to be able to
access objects within linear lists.
You figured it out, but just to sum up -- g would equal
timeOut(wiper) which is a string, and timeOut(wiper) is a timeout
OBJECT, so it's correct.
[To remove yourself from this list, or to
Nah, you just have to think about it differently:
g = timeout( QUOTE time QUOTE )
put g
-- timeout(time)
put value(g)
-- timeOut(time)
On 12/11/03 4:24 PM, Mendelsohn, Michael [EMAIL PROTECTED]
spewed forth:
...and I've been thinking, it seems difficult at best to be able to
access
You could also do
Repeat with t = 1 to the timeoutList
if the timeoutlist[t].name = whatever
End repeat
(timeoutObject.name
Description
This timeout property is the name of the timeout object as defined when the
object is created. The new() command is used to create timeout objects.
Michael,
Put the timeoutlist[1] works, but I need to access by name, not item,
because there may be more than one timeout going on. Any ideas?
The timeout list is a _linear_ list of timeout object references, therefore you don't
get named access. Your getPos call will fail because in essence
Can one imply from this statement, that JT has returned to the nest?
Irv
At 2:01 PM -0800 12/11/03, Thomas Higgins wrote:
I just strolled over to the source (John Henry Thompson, father of Lingo)
and got the scoop:
snipitude
--
Multimedia Wrangler.
[To remove yourself from this list, or to
Can one imply from this statement, that JT has returned to the nest?
Either that or you can imply that I live with JHT... :\
(your implication is correct though, mine is in jest)
Cheers,
Tom Higgins
Product Specialist - Director Team
Macromedia
DIRECTOR, de lekkerste!
...
[To remove
At 15:27 Uhr -0800 11.12.2003, Irv Kalb wrote:
Can one imply from this statement, that JT has returned to the nest?
if so then hopefully not only for a visit...
;-)
--
|||
a¿ex
--
[To remove yourself from this list, or to change to digest mode, go to
http://www.penworks.com/lingo-l.cgi To
This is excellent news for the Director community!
Sending one large e-cake to celebrate his return.
Irv
At 4:01 PM -0800 12/11/03, Thomas Higgins wrote:
Can one imply from this statement, that JT has returned to the nest?
Either that or you can imply that I live with JHT... :\
(your
On Thursday, December 11, 2003, at 07:49 PM, Irv Kalb wrote:
This is excellent news for the Director community!
Sending one large e-cake to celebrate his return.
Yes.
--
Troy
RPSystems, Ltd.
http://www.rpsystems.net
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Can one imply from this statement, that JT has returned to the nest?
DIRECTOR, de lekkerste!
Following along this path of implications, this suggests Director may yet
regain it's most delicious status ...
[To remove yourself from this list, or to change to digest mode, go to
Following along this path of implications, this suggests
Director may yet regain it's most delicious status ...
Well in my own mind, along with Febo, Director is already de lekkerste. Always has
been, always will be.
Cheers,
Tom Higgins
Product Specialist - Director Team
Macromedia
Well in my own mind, along with Febo, Director is already de lekkerste.
Always has been, always will be.
I'd have to agree!
-Sean.
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On 12/11/03 7:49 PM, Irv Kalb [EMAIL PROTECTED] spewed forth:
This is excellent news for the Director community!
Sending one large e-cake to celebrate his return.
Irv
I don't mean to sound negative -- but why exactly? Does this ensure that
Director will see the rapid development that
On Thursday, December 11, 2003, at 11:24 PM, grimmwerks wrote:
I _really_ don't want to be one of those troll naysayers -- hell I
feed my
family from ONLY director development -- but I've got to start facing
facts
that there are 1000 flash gigs to 1 director gig
And probably 2,000 flash
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