hi,
I guess there is an obvious command for this, I just don't know it.
How can I compare two directory structures if the content is the same
*disregarding*
actual file content, or comparing that only if the file names and
sizes are the same?
As I understand diff -r would do it but it would als
If you want to compare filenames, size, ownership and last update time:
cd directory1
ls -alR > /tmp/dirlist.1
cd directory2
ls -alR > /tmp/dirlist.2
diff /tmp/dirlist.1 /tmp/dirlist.2
If you want to compare only sizes and filenames:
cd directory1
ls -alR | cut -d\ -f 5- > /tmp/di
Gabor Szabo writes:
> hi,
>
> I guess there is an obvious command for this, I just don't know it.
>
> How can I compare two directory structures if the content is the same
> *disregarding*
> actual file content, or comparing that only if the file names and
> sizes are the same?
>
> As I understan
Hi Gabor,
You can use rsync.
rsync -avn a b
-n is the flag for dry-run.
If you add the flag -c then it will compute the checksum for every file. If
-c is not used, then it will relay on timestamp and size of file for
comparison.
output:
$ rsync -avn a b
sending incremental file list
a/
a/file
se
