One of the more common cases of allocation size calculations is finding the
size of a structure that has a zero-sized array at the end, along with memory
for some number of elements for that array. For example:

struct foo {
    int stuff;
    void *entry[];
};

instance = kzalloc(sizeof(struct foo) + sizeof(void *) * count, GFP_KERNEL);

Instead of leaving these open-coded and prone to type mistakes, we can now
use the new struct_size() helper:

instance = kzalloc(struct_size(instance, entry, count), GFP_KERNEL);

This code was detected with the help of Coccinelle.

Signed-off-by: Gustavo A. R. Silva <gust...@embeddedor.com>
---
 drivers/uwb/drp-ie.c | 5 ++---
 1 file changed, 2 insertions(+), 3 deletions(-)

diff --git a/drivers/uwb/drp-ie.c b/drivers/uwb/drp-ie.c
index 1d2a939cfcf8..ed993e363472 100644
--- a/drivers/uwb/drp-ie.c
+++ b/drivers/uwb/drp-ie.c
@@ -125,9 +125,8 @@ static struct uwb_ie_drp *uwb_drp_ie_alloc(void)
 {
        struct uwb_ie_drp *drp_ie;
 
-       drp_ie = kzalloc(sizeof(struct uwb_ie_drp) +
-                       UWB_NUM_ZONES * sizeof(struct uwb_drp_alloc),
-                       GFP_KERNEL);
+       drp_ie = kzalloc(struct_size(drp_ie, allocs, UWB_NUM_ZONES),
+                        GFP_KERNEL);
        if (drp_ie)
                drp_ie->hdr.element_id = UWB_IE_DRP;
        return drp_ie;
-- 
2.20.1

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