Use parentheses around uses of the argument in u64_to_user_ptr() to ensure
that the cast doesn't apply to part of the argument.
There are existing uses of the macro of the form `u64_to_user_ptr(A + B)`,
which expands to `(void __user *)(uintptr_t)A + B` (the cast applies to the
first operand of the addition, the addition is a pointer addition). This
happens to still work as intended, the semantic difference doesn't cause a
difference in behavior.
But I want to use u64_to_user_ptr() with a ternary operator in the
argument, like so: `u64_to_user_ptr(A ? B : C)`. This currently doesn't
work as intended.
Reviewed-by: Mukesh Ojha <mo...@codeaurora.org>
Signed-off-by: Jann Horn <ja...@google.com>
---
include/linux/kernel.h | 4 ++--
1 file changed, 2 insertions(+), 2 deletions(-)
diff --git a/include/linux/kernel.h b/include/linux/kernel.h
index 34a5036debd3..2d14e21c16c0 100644
--- a/include/linux/kernel.h
+++ b/include/linux/kernel.h
@@ -47,8 +47,8 @@
#define u64_to_user_ptr(x) ( \
{ \
- typecheck(u64, x); \
- (void __user *)(uintptr_t)x; \
+ typecheck(u64, (x)); \
+ (void __user *)(uintptr_t)(x); \
} \
)
--
2.21.0.392.gf8f6787159e-goog
