On Fri, Aug 29, 2014 at 11:16 AM, Oleg Nesterov wrote:
> interrupted_kernel_fpu_idle() tries to detect if kernel_fpu_begin()
> is safe or not. In particulat it should obviously deny the nested
> kernel_fpu_begin() and this logic doesn't look clean.
>
> If use_eager_fpu() == T we rely on a)
On Fri, Aug 29, 2014 at 11:16 AM, Oleg Nesterov o...@redhat.com wrote:
interrupted_kernel_fpu_idle() tries to detect if kernel_fpu_begin()
is safe or not. In particulat it should obviously deny the nested
kernel_fpu_begin() and this logic doesn't look clean.
If use_eager_fpu() == T we rely on
interrupted_kernel_fpu_idle() tries to detect if kernel_fpu_begin()
is safe or not. In particulat it should obviously deny the nested
kernel_fpu_begin() and this logic doesn't look clean.
If use_eager_fpu() == T we rely on a) __thread_has_fpu() check in
interrupted_kernel_fpu_idle(), and b) on
interrupted_kernel_fpu_idle() tries to detect if kernel_fpu_begin()
is safe or not. In particulat it should obviously deny the nested
kernel_fpu_begin() and this logic doesn't look clean.
If use_eager_fpu() == T we rely on a) __thread_has_fpu() check in
interrupted_kernel_fpu_idle(), and b) on
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