On Fri, 2016-11-04 at 19:39 +0100, Sebastian Andrzej Siewior wrote:
> Debian gcc's is nowdays compiled with --enable-default-pie which means it does
> -fPIE by default. This breaks atleast x86-64 compiles.
> This is the third attempt to fix it, this time by using runtime detection of
> the -fno-PIE
On Fri, Nov 04, 2016 at 07:39:37PM +0100, Sebastian Andrzej Siewior wrote:
> Debian gcc's is nowdays compiled with --enable-default-pie which means it does
Ho humm, there it is:
$ gcc -### /usr/include/stdlib.h 2>&1 | grep -o -- "--enable-default-pie"
--enable-default-pie
For all three:
Tested-
On 11/04/16 11:39, Sebastian Andrzej Siewior wrote:
> Debian gcc's is nowdays compiled with --enable-default-pie which means it does
> -fPIE by default. This breaks atleast x86-64 compiles.
> This is the third attempt to fix it, this time by using runtime detection of
> the -fno-PIE compiler switch
On Fri, Nov 04, 2016 at 07:39:37PM +0100, Sebastian Andrzej Siewior wrote:
> Debian gcc's is nowdays compiled with --enable-default-pie which means it does
> -fPIE by default. This breaks atleast x86-64 compiles.
> This is the third attempt to fix it, this time by using runtime detection of
> the -
Debian gcc's is nowdays compiled with --enable-default-pie which means it does
-fPIE by default. This breaks atleast x86-64 compiles.
This is the third attempt to fix it, this time by using runtime detection of
the -fno-PIE compiler switch (it was introduced in gcc 3.4, min required gcc is
currentl
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