Hi, PC
Thank you every much!
-Original Message-
From: Paul Clarke [mailto:p...@us.ibm.com]
Sent: 2019年4月15日 20:53
To: Linhaifeng ; linux-perf-us...@vger.kernel.org;
linux-kernel@vger.kernel.org
Subject: Re: perf tools:Is there any tools to found out the max latency by irq
or cpu idle
Hi,
Thank you every much!
I found MSI in my system too and there are some errors found in bios log.
Replace the memorys can fix it.
L2GW_2680:/home/fsp/ycb # perf stat -C 1-11,14-25,29-39,42-52 --smi-cost
^C
Performance counter stats for 'CPU(s) 1-11,14-25,29-39,42-52':
SMI cycles% SMI#
Em Mon, Apr 15, 2019 at 07:52:59AM -0500, Paul Clarke escreveu:
> On 4/13/19 1:01 AM, Linhaifeng wrote:
> > Sorry, the value 131081408 is just for example. Actually the result is like
> > this:
> > sqrt 2019-04-10 23:53:50: 43968
> > sqrt 2019-04-10 23:53:51: 44060
> > sqrt 2019-04-10
On 4/13/19 1:01 AM, Linhaifeng wrote:
> Sorry, the value 131081408 is just for example. Actually the result is like
> this:
> sqrt 2019-04-10 23:53:50: 43968
> sqrt 2019-04-10 23:53:51: 44060
> sqrt 2019-04-10 23:53:52: 49012
> sqrt 2019-04-10 23:53:53: 38172
> sqrt 2019-04-10 23:53:54:
On 4/13/19 2:01 AM, Linhaifeng wrote:
> Sorry, the value 131081408 is just for example. Actually the result is like
> this:
> sqrt 2019-04-10 23:53:50: 43968
> sqrt 2019-04-10 23:53:51: 44060
> sqrt 2019-04-10 23:53:52: 49012
> sqrt 2019-04-10 23:53:53: 38172
> sqrt 2019-04-10 23:53:54:
Sorry, the value 131081408 is just for example. Actually the result is like
this:
sqrt 2019-04-10 23:53:50: 43968
sqrt 2019-04-10 23:53:51: 44060
sqrt 2019-04-10 23:53:52: 49012
sqrt 2019-04-10 23:53:53: 38172
sqrt 2019-04-10 23:53:54: 131081408
sqrt 2019-04-10 23:53:55: 43600
sqrt
On 4/11/19 8:57 PM, Linhaifeng wrote:
> Hi,
> I have a single thread application like this:
>
> While (1) {
> start = rdtsc();
> sqrt (1024);
> end = rdtsc();
> cycles = end – start;
> printf("cycles: %d-%02d-%02d %02d:%02d:%02d: %lu\n",
> 1900+timeinfo->tm_year,
Hi,
I have a single thread application like this:
While (1) {
start = rdtsc();
sqrt (1024);
end = rdtsc();
cycles = end – start;
printf("cycles: %d-%02d-%02d %02d:%02d:%02d: %lu\n",
1900+timeinfo->tm_year, 1+timeinfo->tm_mon, timeinfo->tm_mday,
timeinfo->tm_hour,
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