Hi,
I'm looking at user_enable_block_step() in current kernels and it has
the following:
#ifdef CONFIG_PPC_ADV_DEBUG_REGS
task->thread.dbcr0 &= ~DBCR0_IC;
task->thread.dbcr0 = DBCR0_IDM | DBCR0_BT;
regs->msr |= MSR_DE;
Should it be as follows?
task->thread.dbcr0 |= DBCR0_IDM | DBCR0_BT;
If not, then what's the point of clearing the DBCR0_IC bit in the
previous line?
Chris
--
Chris Friesen
Software Designer
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