On Mon, Jun 18, 2001 at 11:56:59AM +0100, David Cantrell wrote:
> On Mon, Jun 18, 2001 at 08:29:18AM +0200, Philip Newton wrote:
> > Chris Benson wrote:
> > > Mmmm, so if there are 3 water lilies with circular leaves, what
> > > is the largest they can grow on the surface of a sphere without
> >
On Mon, Jun 18, 2001 at 07:29:28AM +0100, Roger Burton West wrote:
> On Mon, Jun 18, 2001 at 12:01:05AM +0100, Chris Benson wrote:
> >Mmmm, so if there are 3 water lilies with circular leaves, what is the
> >largest they can grow on the surface of a sphere without overlap?
>
> Looks like evenly
On Mon, Jun 18, 2001 at 12:01:05AM +0100, Chris Benson wrote:
>Mmmm, so if there are 3 water lilies with circular leaves, what is the
>largest they can grow on the surface of a sphere without overlap?
>On a circle it's easy to see it's just less than the radius of the
>circle. Not so easy with
Chris Benson wrote:
> Mmmm, so if there are 3 water lilies with circular leaves, what
> is the largest they can grow on the surface of a sphere without
> overlap? On a circle it's easy to see it's just less than the
> radius of the circle. Not so easy with a sphere.
Well, first off, the circles
On Sun, Jun 17, 2001 at 08:58:35PM +0100, Greg McCarroll wrote:
> * Chris Benson ([EMAIL PROTECTED]) wrote:
> > On Sun, Jun 17, 2001 at 06:58:03PM +0100, Roger Burton West wrote:
> > > On Sun, Jun 17, 2001 at 06:52:04PM +0100, Greg McCarroll wrote:
> > >
> the main problem is for low values of N,
* Chris Benson ([EMAIL PROTECTED]) wrote:
> On Sun, Jun 17, 2001 at 06:58:03PM +0100, Roger Burton West wrote:
> > On Sun, Jun 17, 2001 at 06:52:04PM +0100, Greg McCarroll wrote:
> >
> > >Ok, now how can you distribute N points around the origin in _3_ dimensions,
> > >again all of them at the sa
On Sun, Jun 17, 2001 at 06:58:03PM +0100, Roger Burton West wrote:
> On Sun, Jun 17, 2001 at 06:52:04PM +0100, Greg McCarroll wrote:
>
> >Ok, now how can you distribute N points around the origin in _3_ dimensions,
> >again all of them at the same distance from the origin? Obviously
> >there will
How about drawing a 3D shape (depending upon the value of N) with equal
distances between neighbour nodes and equal angles between the edges? All the
nodes lie on the imaginary sphere and the distance to the center is the same.
Thus you get one and only one shape for each value of N. You can rotat
On Sun, Jun 17, 2001 at 06:52:04PM +0100, Greg McCarroll wrote:
>Ok, now how can you distribute N points around the origin in _3_ dimensions,
>again all of them at the same distance from the origin? Obviously
>there will be an imaginary sphere again, but where do you put the points.
Best general
