Hi,
I'm trying to draw a line given an angle, magnitude, x0 and y0
location on a 2d line plot. I use the "cosine" and "sine" to find
the x1 and y1 locations so that I can draw a line segment from x0, y0
to x1, y1. This works fine on a 200 x 200 (Width x Height) pixel
graph. However, I have
John Hunter wrote:
>> "Karl" == Karl Guertin <[EMAIL PROTECTED]> writes:
>>
>
> Karl> I have a very customized matplotlibrc for rendering charts
> Karl> for web pages. The biggest change is that I render
> Karl> everything white on black by default. This has worked
John Hunter wrote:
>> "David" == David Goldsmith <[EMAIL PROTECTED]> writes:
>>
>
> David> OK, I was afraid of that; in that case, is there some way
> David> to get the height and width of the legend (so I can do what
> David> I want programatically)? Thanks again,
John Hunter wrote:
> The legend placement is done dynamically at draw time,
Ah, so it looks like it does make sense for the user to specify an
alignment, and have it figured out at draw time.
> It might be better to patch legend directly to do what you want and
> send the patch our way. Or subc
On Thu, 26 Oct 2006, Michele Vallisneri apparently wrote:
> I've been building matplotlib 0.87.7 on a 10.4.7 OS X system, with
> Universal Python 2.4.3 from pythonmac.org. I've been following
> instructions at
> http://sourceforge.net/mailarchive/message.php?msg_id=36901627
Please keep postin
> "David" == David Goldsmith <[EMAIL PROTECTED]> writes:
David> OK, I was afraid of that; in that case, is there some way
David> to get the height and width of the legend (so I can do what
David> I want programatically)? Thanks again,
Again, afraid not. At least nothing obvious.
John Hunter wrote:
>> "David" == David Goldsmith <[EMAIL PROTECTED]> writes:
>>
>
> David> Hi! OK, loc=(a,b) positions the legend, and appears to
> David> place the lower left corner at (a,b) (axes coords.), right?
>
> yes
>
> David> Is there some way to say that (
> "David" == David Goldsmith <[EMAIL PROTECTED]> writes:
David> Hi! OK, loc=(a,b) positions the legend, and appears to
David> place the lower left corner at (a,b) (axes coords.), right?
yes
David> Is there some way to say that (a,b) should specify the
David> location of, say
> "Eric" == Eric Firing <[EMAIL PROTECTED]> writes:
>> I am trying to build Matplotlib 0.87.7 on an RHEL 4.4-derived
>> system, with Python 2.3.4. I am running into a weird
>> problem. When I do "python setup.py build", I get the following
>> error:
It looks like this bug
htt
Hi,
I've been building matplotlib 0.87.7 on a 10.4.7 OS X system, with
Universal Python 2.4.3 from pythonmac.org. I've been following
instructions at
http://sourceforge.net/mailarchive/message.php?msg_id=36901627
to create a universal library, downloading and compiling my own
libpng and l
> Once when I found that NumPy released its version 1.0rc3,
> I happily upgraded NumPy from 1.0rc1 to 1.0rc3 under WindowsXP.
> A nightmare just happened. Matplotlib failed to run with NumPy 1.0
> rc3,
> and I cannot found a NumPy 1.0rc1 on its download page.
> Will matplotlib upgrade for NumPy 1
Stephen,
On the dev list was an ANN post which stated that 0.87.7:
This release is compiled against numpy-1.0 final. The binaries are
fresh on sourceforge, so they may take some time to propagate to the
mirrors.
http://cheeseshop.python.org/pypi/matplotlib/
http://sourceforge.net/project/showfi
Sorry if this has been answered already, but I'm having trouble
finding the answer--
What version of matplotlib is compatible with numpy 1.0 (final)? Or,
should I continue to use numpy-1.0rc2 w/ mpl 0.87.7? I'm building from
source on mac os using fink, and have had no trouble until numpy
1.0rc3 c
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