On Dec 18, 2007 9:47 PM, Bryan Fodness <[EMAIL PROTECTED]> wrote:
> I do want a rectangle. And, I have tried,
>
> axvline(x=x1, ymin=y1, ymax=y2)
> axvline(x=x2, ymin=y1, ymax=y2)
> axhline(y=y1, xmin=x1, xmax=x2)
> axhline(y=y2, xmin=x1, xmax=x2)
>
You can either use the plot function "fill"
I
I do want a rectangle. And, I have tried,
axvline(x=x1, ymin=y1, ymax=y2)
axvline(x=x2, ymin=y1, ymax=y2)
axhline(y=y1, xmin=x1, xmax=x2)
axhline(y=y2, xmin=x1, xmax=x2)
On Dec 18, 2007 10:40 PM, John Hunter <[EMAIL PROTECTED]> wrote:
> On Dec 18, 2007 9:00 PM, Bryan Fodness <[EMAIL PROTECTED]>
On Dec 18, 2007 9:00 PM, Bryan Fodness <[EMAIL PROTECTED]> wrote:
> I would like to draw a polygon using a x1, x2, y1, and y2.
At a minimum, x1, x2, y1, and y2 define a line segment, or at most a
rectangle. You say a "polygon". What exactly do you mean, and what
have you tried (code please)?
JD
I would like to draw a polygon using a x1, x2, y1, and y2.
I tried to use axhline and axvline with the min and max values but it does
give the desired result. It changes the axis limits and does not draw a
line at all.
Any help would be appreciated.
Bryan
--
"The game of science can accurately
On Tuesday 18 December 2007 10:55:36 am Peter-Jan Randewijk wrote:
> Darren,
>
> Thanks for the quick reply... It works like a charm... Somehow I
> missed the post in the userslist...
You're off the hook :) It was posted at the sourceforge bugtracker, not on the
mailing list.
> Op 2007/12/18 1
Darren,
Thanks for the quick reply... It works like a charm... Somehow I
missed the post in the userslist...
Kind regards,
Peter-Jan
Op 2007/12/18 17:25, het Darren Dale die volgende geskryf:
> Somebody reported it right after 0.91.1 was released. It has been fixed in
> svn. To hold you ove
Somebody reported it right after 0.91.1 was released. It has been fixed in
svn. To hold you over until the next release, I think you just need to update
your matplotlib/__init__.py and matplotlib/rcsetup.py.
On Tuesday 18 December 2007 10:07:28 am Peter-Jan Randewijk wrote:
> Dear Darren,
>
> I
Dear Darren,
I know "text.latex.preamble" is not supported, but since I upgraded to
Matplotlib 0.91.1 my latex preamble code which was working perfectly
well in 0.90.1, now gives my the follow errors (both on openSUSE & XP):
In [1]: run overlap_vs_concentrated.py
C:\Python\lib\site-packages\m
Yes, I think strpdate2num is based on dateutil.parser.parse thast's why I
tried dayfirst=True which is used with dateutil.parser.parse.
It would be funny if from a list of string, it could be automatically try to
decide between day/month/year, month/day/year format... (it´s a joke)
--
Hi Emmanuel,
look at dateutil.parser.parse, there is exactly what you search.
Le mardi 18 décembre 2007, Emmanuel a écrit :
> Ok, thank you!
>
> I'm missing an option to (easily) use date that start with the day
> day/month/year (it is the case in Brazil and France for example)
>
> I'm using somet
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