I'm afraid the scatter plot does not allow afterward adjustment with size
currently (by using setp).
Probably you should redraw the scatter points with different sizes. like
for x,y,z in zip(xlist,ylist,sizelist):
m.scatter(x,y,s=z)
if you question is to change the real 2km or 1.5km to the s
Hi all,
I'm trying to do a scatter plot within a map created by basemap.
m = Basemap(projection='ortho',lat_0=45,lon_0=0,resolution='l')
X,Y = m(lon,lat)
m.scatter(X,Y,s=sizes,c=data,edgecolor='none')
This works fine. Now I want to change the sizes of the markers so that the
marker at point A h
Unfortunately, I don't think there is a way to do this at present. Out
of curiosity, what is the use case?
I wonder if the best way to do this would be to expose the stroking to
the Python level, so given a line one could get a filled path that is
the stroked line. I'm not sure how else this
>
> Message: 1
> Date: Fri, 12 Apr 2013 13:55:32 +0400
> From: Bakhtiyor Zokhidov
> Subject: [Matplotlib-users] Impossible to draw a direction of arrows
> in Matplotlib???
>
> Hi,
> I have encountered some problem while I was drawing a direction of
> arrow. I have point (x,y) coordinates
I'm not sure that I understand exactly what you are trying to do, but
you may want to look into Matplotlib annotation. Here's a really quick
example:
import matplotlib.pyplot as plt
plt.annotate('', (1, 1), (0, 0),
arrowprops=dict(facecolor='black'))
plt.axis([-1, 2, -1, 2])
plt.show()
Hi,
I have encountered some problem while I was drawing a direction of
arrow. I have point (x,y) coordinates and angle of them. What I want to
do is that to draw arrow according to the given angle (just to show the
point direction as an arrow in each point coordinate). Here, we should
assume coord
I have a collection of Patches and Lines that have their coordinates in
data space, i.e. like in the following example:
import matplotlib.pyplot as plt
import matplotlib.patches as mpatches
import matplotlib.collections as mcollections
import matplotlib.lines as mlines
fig = plt.figure()
ax = fi
