Hi everyone. I was trying to produce an irregular heat map broken down by
day/weeks, as excellently shown here:
http://revolution-computing.typepad.com/.a/6a010534b1db25970b0120a63e9936970b-500wi
(source:
http://stackoverflow.com/questions/2076370/most-underused-data-visualization)
How would y
On Sun, 6 Mar 2011 21:47:04 +0900
Jae-Joon Lee wrote:
> > Ok, I can understand that, but shouldn't all artists used to construct the
> > picture, as suptitle, be considered?
>
> I think considering all the artists is not very practical (as some of
> them could have spline paths), but what we
On Mon, 7 Mar 2011 13:41:49 -0600
Benjamin Root wrote:
> > I've
> > been using matplotlib a lot the last few months and was totally
> > unaware that pyplot was "required". Good thing I read this message! :-)
I'm glad I'm not the only one :)
> > > The interface should create the figure objects
On Tue, 8 Mar 2011 02:35:52 +0900
Jae-Joon Lee wrote:
> On Mon, Mar 7, 2011 at 8:22 PM, Yuri D'Elia wrote:
> > With matplotlib, I have to do the following:
> >
> > legend(bbox_to_anchor=(1, 1 + ?), loc=2)
> >
> > but how do I calculate the vertical location
On Tue, 8 Mar 2011 02:03:54 +0900
Jae-Joon Lee wrote:
> On Mon, Mar 7, 2011 at 7:36 PM, Yuri D'Elia wrote:
> In fact, supporting the "bbox_inches" is a real hack.
> As I mentioned in my previous email, matplotlib artists can have
> spline paths. And artists can also
On Mon, 7 Mar 2011 09:25:23 -0600
Benjamin Root wrote:
> The problem is that you are creating your figure wrong. Try this:
>
> import matplotlib as mpl
> mpl.use("Agg")
> import matplotlib.pyplot as plt
>
> fig = plt.figure(figsize=(20, 20))
> ax = fig.add_subplot(111)
> ax.set_title("Subtitle
On Mon, 7 Mar 2011 09:08:29 -0600
Benjamin Root wrote:
> Matplotlib is designed to give you maximum control over the figure elements
> while still maintaining sensible defaults. This is helpful in some cases,
> and not so helpful in others. In your case of placing a legend outside an
> axes, ca
On Mon, 7 Mar 2011 11:36:45 +0100
Yuri D'Elia wrote:
> On Fri, 4 Mar 2011 14:57:34 -0600
> Benjamin Root wrote:
>
> > Which version of matplotlib are you using? This example works for me using
> > the latest matplotlib from source. Also, why the awkward usage and
Hi everyone. I'm a newbye to matplotlib, so excuse my naive questions. I have a
large experience with gnuplot and asymptote, and I only recently started to
experiment with matplotlib.
Some background: I'm trying to use matplotlib mostly for complex plots with a
lot of data. Gnuplot is usually f
On Fri, 4 Mar 2011 14:57:34 -0600
Benjamin Root wrote:
> Which version of matplotlib are you using? This example works for me using
> the latest matplotlib from source. Also, why the awkward usage and
Yes, with matplotlib 1.0 bbox_extra_artists now works.
I consider bbox_extra_artists some ki
On Wed, 2 Mar 2011 22:01:02 +0900
Jae-Joon Lee wrote:
> >> > Is this a bug?
> >>
> >> Unfortunately, bbox_inches option is never meant to be complete in
> >> figuring out the exact size of the figure area.
> >
> > Why not? What's the purpose of bbox_inches='tight' otherwise?
>
> Figuring out
On Tue, 1 Mar 2011 12:44:20 +0900
Jae-Joon Lee wrote:
> > Is this a bug?
>
> Unfortunately, bbox_inches option is never meant to be complete in
> figuring out the exact size of the figure area.
Why not? What's the purpose of bbox_inches='tight' otherwise?
> However, you can use "bbox_extra_a
In the following:
<<<
import matplotlib as mpl
import matplotlib.figure
import matplotlib.backends.backend_agg
fig = mpl.figure.Figure()
cvs = mpl.backends.backend_agg.FigureCanvasAgg(fig)
fig.set_size_inches((20,20))
fig.suptitle("Horray!", fontsize=20)
plot = fig.add_subplot(111)
plot.s
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