Try this.
def get_indx(irow, icol):
return irow*4+icol
ax = plt.subplot(gs[get_indx(0,3):get_indx(3,3)])
With 1d slicing, the axes will occupy the rectangle defined by the
start and stop location.
For example,
gs[i:j]
will occupy the rectangular area between
gs[i] and gs[j-1].
Let me kno
On 10/25/2010 11:18 AM, Jae-Joon Lee wrote:
> On Mon, Oct 25, 2010 at 10:45 PM, Nikolaus Rath wrote:
>> So I have to instantiate GridSpec with a (rows, column), but when I
>> index the grid I have to use (column, row).
>>
>> Is there any reason for this counterintuitive behaviour?
>>
>
> This is
On Mon, Oct 25, 2010 at 10:45 PM, Nikolaus Rath wrote:
> So I have to instantiate GridSpec with a (rows, column), but when I
> index the grid I have to use (column, row).
>
> Is there any reason for this counterintuitive behaviour?
>
This is not an intended behavior but a bug which affects a grid
Hello,
I just noticed that in order to get a 3 row by 4 column grid, I have to
do
import matplotlib.pyplot as plt
from matplotlib.gridspec import GridSpec
def make_ticklabels_invisible(fig):
for i, ax in enumerate(fig.axes):
ax.text(0.5, 0.5, "ax%d" % (i+1), v
