Hi,
I just installed matplotlib 0.99.0 and I see that this problem is
still there.
The command plot(a,ls='steps') is equivalent to plot(a,ls='steps-pre')
and both cause the first value of the array to NOT be plotted. This
is REALLY not what should happen when one plots an array with several
On Fri, Jul 17, 2009 at 5:15 PM, Paul Ray wrote:
>
>
> Ryan Krauss-2 wrote:
>>
>> RTFM:
>>
>> plot(t,y, drawstyle='steps-post')
>>
>>
>
> Actually, 'steps-pre' (which is the default) and 'steps-post' seem to have
> swapped definitions.
> Here is what the docs say:
> *where*: [ 'pre' | 'post' | '
Ryan Krauss-2 wrote:
>
> RTFM:
>
> plot(t,y, drawstyle='steps-post')
>
>
Actually, 'steps-pre' (which is the default) and 'steps-post' seem to have
swapped definitions.
Here is what the docs say:
*where*: [ 'pre' | 'post' | 'mid' ]
If 'pre', the interval from x[i] to x[i+1] has le
RTFM:
plot(t,y, drawstyle='steps-post')
This was really helpful:
http://matplotlib.sourceforge.net/examples/pylab_examples/set_and_get.html
especially
>>> line, = plot([1,2,3])
>>> setp(line, linestyle='--')
On Fri, May 15, 2009 at 6:52 PM, Ryan Krauss wrote:
> Oh, and in case it matters
Oh, and in case it matters I am running
In [36]: matplotlib.__version__
Out[36]: '0.98.5.2'
on Ubuntu 9.04 (with the rather lame name of Jaunty Jackolope).
On Fri, May 15, 2009 at 6:51 PM, Ryan Krauss wrote:
> I think I used to use plot with linestyle='steps' to plot data for
> zero-order hold
