I'm hoping to generate a line plot where the color of each pixel on
the plot is given by linearly interpolating the colormap from each
point specified in the line, instead of having the whole line be a
solid color. I can "mock this up" by doing a scatter plot where the
points are much closer toget
Hi Erik,
On Mon, May 4, 2009 at 09:22, Erik Tollerud wrote:
> I'm hoping to generate a line plot where the color of each pixel on
> the plot is given by linearly interpolating the colormap from each
> point specified in the line, instead of having the whole line be a
> solid color. I can "mock t
Hi,
I'm new with matplotlib.
I need to make a graph with the X axis represents time in hours and
minutes. My script don't works, I want to display all the values of time
that I have.
I use a list of string like this :
t=['0015', '0030', '0045', '0100', '0115', '0130', '0145', '0200',
'0215', '0230
Hi,
Could you send your setup.
I'm not expert but I can check it.
/olivier
-Original Message-
From: sordnay [mailto:sord...@gmail.com]
Sent: jeudi 30 avril 2009 18:23
To: matplotlib-users@lists.sourceforge.net
Subject: [Matplotlib-users] mathtext and py2exe
hello,
I have written a pro
Hello,
why is the matplotlib.sphinxext.mathmpl been taken off the SVN repository:
https://matplotlib.svn.sourceforge.net/svnroot/
matplotlib/trunk/matplotlib/doc/sphinxext/
I have been using it to parse formulas in my documentation source.
It is still used by the Sphinx configuration from mpl svn
Hi,
why is $\sum M_\theta$ rendered correctly, but $M_\theta$" is printed as
"_\theta$"?
Regards,
wr
--
Register Now & Save for Velocity, the Web Performance & Operations
Conference from O'Reilly Media. Velocity feature
Hi John,
On Sun, May 3, 2009 at 00:21, John Hunter wrote:
> On Sat, May 2, 2009 at 9:42 AM, Sandro Tosi wrote:
>>
>> Hi all!
>> I'd like to embed a mpl graph into a GTK application (and for that
>> embedding_in_gtk*.py examples are fine) but I would also like to
>> dynamically update the graph w
Hello,
could you please provide a stand-alone example of what is failing and what
version/ backend you are using?
for me the following works (with mpl-0.98.6svn and backend 'GTKAgg'):
text(0.25, 0.75, r"$M_\theta$")
regards Matthias
PS: You can access the used backend and the matplotlib versi
I believe that it is just moved to another directory (lib/matplotlib/sphinxext).
http://www.nabble.com/Re%3A-Sphinx-custom-extension-mess%2C-and-patches-p22037746.html
Regards,
-JJ
On Mon, May 4, 2009 at 11:02 AM, Timmie wrote:
> Hello,
> why is the matplotlib.sphinxext.mathmpl been taken
On Mon, May 4, 2009 at 2:22 AM, Erik Tollerud wrote:
> I'm hoping to generate a line plot where the color of each pixel on
> the plot is given by linearly interpolating the colormap from each
> point specified in the line, instead of having the whole line be a
> solid color. I can "mock this up"
I need to distribute matplotlib as part of a large and somewhat
heterogeneous package of Python-based software. On Macs, lapack is
installed by default, and I can rely on the linking working regardless of
which OS version it was compiled on (we use 10.4.11, but it runs fine on
10.5). On Linux, it
Hi,
Just compile numpy on a system that doesn't have lapack3 installed.
Matthieu
2009/5/4 Nathaniel Echols :
> I need to distribute matplotlib as part of a large and somewhat
> heterogeneous package of Python-based software. On Macs, lapack is
> installed by default, and I can rely on the linki
Eric and Thomas,
Thanks for your help. I was able to get it plotting MUCH faster. Here's my
code:
#!/usr/bin/env python
from pylab import *
from scipy import *
ion()
img = standard_normal((50,100))
image = imshow(img,interpolation='nearest',animated=True,label="blah")
for k in range(1,100):
On Mon, May 4, 2009 at 10:50 AM, Matthieu Brucher <
matthieu.bruc...@gmail.com> wrote:
> Just compile numpy on a system that doesn't have lapack3 installed.
>
Unfortunately, this is going to be difficult - our build process is very
automated (done every night) and we use these systems for other t
Hello,
Is it possible to have basemap plot in the usual way on a polar-projection
subplot?
I want to do something like this:
fig = plt.figure(figsize)
ax = fig.add_subplot(111, polar=True)
m = Basemap(...)
m.drawcoastlines(...)
etc.
The reason I want to have a polar-projection plot is because I
jtamir wrote:
> Hello,
>
> Is it possible to have basemap plot in the usual way on a polar-projection
> subplot?
>
No.
> I want to do something like this:
> fig = plt.figure(figsize)
> ax = fig.add_subplot(111, polar=True)
> m = Basemap(...)
> m.drawcoastlines(...)
> etc.
>
> The reason I want
The docs
http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.legend
suggest that
loc=(0.5,0.5)
is equivalent to
loc='center'
but it is not. How can I center the legend
relative to the x-axis?
It seems to me that I need to be able to set
not only the coordinates but also what p
On Mon, May 4, 2009 at 10:47 PM, Alan G Isaac wrote:
> The docs
> http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.legend
> suggest that
> loc=(0.5,0.5)
> is equivalent to
> loc='center'
> but it is not. How can I center the legend
> relative to the x-axis?
>
As you may ha
18 matches
Mail list logo