Is this the only way to plot a sin from x=0 to x=2pi, but shade where x>0.25pi
and x<0.75pi?
x0 = np.linspace(0.0, 0.25*np.pi, 100)
x1 = np.linspace(0.25*np.pi, 0.75*np.pi, 100)
x2 = np.linspace(0.75*np.pi,2*np.pi, 100)
y0 = np.sin(x0)
y1 = np.sin(x1)
y2 = np.sin(x2)
fig = figure()
ax1 = fig.ad
Chris Michalski wrote:
>
> Offered for those who might have the same need – a Python pchip()
> equivalent ==> pypchip(). Since I'm not sure how attachments work (or
> if they work at all...), I copied the code I used below, followed by a
> PNG showing "success":
Chris,
This looks interestin
On Sat, Aug 29, 2009 at 1:12 PM, Eric Firing wrote:
> This looks interesting. I successfully ran your program by using copy
> and paste to get it into a file, but for the future I certainly
> recommend that you attach such a file directly--file attachments
> generally work very well these days, b
Hi
When I try to import anything from mpl, Python's interpreter exits
without any error.
This happens after the 0.99.0 upgrade. This is example session:
d:\>python
Python 2.6.2 (r262:71605, Apr 14 2009, 22:40:02) [MSC v.1500 32 bit
(Intel)] on win32
Type "help", "copyright", "credits" or "license"
Thanks for the inputs... perhaps it will provide the impetus for
future postings as well...
chris
On Aug 29, 2009, at 11:49 AM, John Hunter wrote:
> On Sat, Aug 29, 2009 at 1:12 PM, Eric Firing
> wrote:
>
>> This looks interesting. I successfully ran your program by using
>> copy
>> and
I'm trying to change the position of the axis label so that it is a
certain number of points off the end of the spine representing the
x-axis. I'm trying to use the transform attribute and the offset_copy
function to say "put the label 5 points right of the end of the spine".
So far, my code
