Eric Firing wrote:
>
> There is a clip function in all three numeric packages, so a native
> clip is being used.
>
> If numpy.clip is actually slower than your version, that sounds like a
> problem with the implementation in numpy. By all logic a single clip
> function should either be the same
David Cournapeau wrote:
[...]
> Ok, I've installed last svn, and now, there is still one function which
> is much slower than a direct numpy implementation, so I would like to
> know if this is inherent to the multiple backend nature of matplotlib or
> not. The functor Normalize uses the clip fu
Eric Firing wrote:
> David,
>
> I have made some changes in svn that address all but one of the points
> you made:
>
> []
>> if self.clip:
>>mask = ma.getmaskorNone(val)
>>if mask == None:
>>val = ma.array(clip(val.filled(vmax), vmin, vmax))
Hello,
I manage to use WXAgg backend by replacing 'TkAgg' with 'WXAgg' inside
matplotlibrc file.
I found that using this wx backend the figure size is smaller than using
TkAgg backend (the default size).
I try to make small experiment by resizing the figure.figsize inside
matplotlibrc file and f
[EMAIL PROTECTED] wrote:
>> Shu: I'd make a mask by finding the points on the grid that are outside
>> your polygon. Then use that mask to create a masked array from your
>> data (masking the points you don't want to plot). matplotlib's contourf
>> knows how to deal with masked arrays (at lea
> Shu: I'd make a mask by finding the points on the grid that are outside
> your polygon. Then use that mask to create a masked array from your
> data (masking the points you don't want to plot). matplotlib's contourf
> knows how to deal with masked arrays (at least when the masked region
>
John Hunter wrote:
[...]
> Simson> To answer Eric's most recent posting:
>
> Simson> 1. I think that scientific notation should not be the
> Simson> default, unless numbers exceed 1E+7.
>
> I agree with this -- scientific notation kicks in too soon IMO. I
> think an rc setting woul
>On the bright side, at least w/matplotlib, you're not paying out the
>wazoo :-) for such things.
>
I actually made the mistake of buying the matlab student edition.
-
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Jo
On Dec 16, 2006, at 8:10 PM, John Hunter wrote:
> Simson> 3. If I was going to make a major change to the API at
> Simson> this point, it would be to make it so that you don't have
> Simson> a class/function/ identifier called "axes" and another one
> Simson> called "axis." I freq
> How is the irregular boundary defined? Is it defined in terms of the
> data you are plotting (i.e. all values exceeding a threshold)? Or, do
> you have the vertices of a polygon you want to use as a mask?
>
> -Jeff
Jeff,
thanks for answering my question. I have the vertices of a polygon
[EMAIL PROTECTED] wrote:
> hi,everybody.first say sorry for my poor english.
> I want to make a contour plot with part out of the irregular boundary
> blank.just as http://www.pyngl.ucar.edu/Examples/Images/ngl05p.3.png
> shows.
> how can i do?
>
>
How is the irregular boundary defined? Is it d
hi,everybody.first say sorry for my poor english.This is my first email
to matplotlib user list.
I want to make a contour plot with part out of the irregular boundary
blank.just as http://www.pyngl.ucar.edu/Examples/Images/ngl05p.3.png
shows.
how can i do?
--
<>
--
hi,everybody.first say sorry for my poor english.
I want to make a contour plot with part out of the irregular boundary
blank.just as http://www.pyngl.ucar.edu/Examples/Images/ngl05p.3.png
shows.
how can i do?
--
<>
-
Tak
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