Re: [Matplotlib-users] Best way to display image from URL in Python3
Thomas, sorry I missed your email. I'll see if I can get a PR pulled together soon-ish. Ryan On Fri, Mar 20, 2015 at 4:32 PM, Ryan Nelson wrote: > A little update. It seems that this seems to be specific to Linux in some > way. I tried the original script from the PR under a couple of conditions: > * on Windows 7 Anaconda Python 2.7 and 3.4 -- everything works both > versions > * on Anaconda Python 2.7 and 3.4 Linux version -- only the 2.7 version > works > * on Gentoo Linux Python 2.7 and 3.4, MPL 1.4.3 -- only the 2.7 version > works > Hope that helps. > > Ryan > > On Fri, Mar 20, 2015 at 3:41 PM, Jerzy Karczmarczuk < > jerzy.karczmarc...@unicaen.fr> wrote: > >> >> Le 20/03/2015 16:57, Ryan Nelson a écrit : >> > For me, if I change the script from the PR to what is shown below, >> > everything works fine in both Python 2.7 and 3.4 (Anaconda >> > environments, everything updated): >> > ## >> > url = 'http://www.libpng.org/pub/png/img_png/pngnow.png' >> > try: >> > import urllib2 >> > data = urllib2.urlopen(url) >> > except Exception: >> > import urllib.request >> > from io import BytesIO >> > data = BytesIO(urllib.request.urlopen(url).read()) >> > >> > from matplotlib import pyplot >> > >> > image = pyplot.imread(data) # crash on py3.x >> > pyplot.imshow(image) >> > pyplot.show() >> > # >> > But as you can see, the Python 3 version requires the addition of >> > BytesIO and read(). I take it that this is not supposed to be the case. >> >> It works for X.png, not for X.jpg. The call of imread() fails then. >> Tested also under 3.4/Anaconda. >> >> Jerzy Karczmarczuk >> >> >> >> -- >> Dive into the World of Parallel Programming The Go Parallel Website, >> sponsored >> by Intel and developed in partnership with Slashdot Media, is your hub >> for all >> things parallel software development, from weekly thought leadership >> blogs to >> news, videos, case studies, tutorials and more. Take a look and join the >> conversation now. http://goparallel.sourceforge.net/ >> ___ >> Matplotlib-users mailing list >> Matplotlib-users@lists.sourceforge.net >> https://lists.sourceforge.net/lists/listinfo/matplotlib-users >> > > -- Dive into the World of Parallel Programming The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Best way to display image from URL in Python3
A little update. It seems that this seems to be specific to Linux in some way. I tried the original script from the PR under a couple of conditions: * on Windows 7 Anaconda Python 2.7 and 3.4 -- everything works both versions * on Anaconda Python 2.7 and 3.4 Linux version -- only the 2.7 version works * on Gentoo Linux Python 2.7 and 3.4, MPL 1.4.3 -- only the 2.7 version works Hope that helps. Ryan On Fri, Mar 20, 2015 at 3:41 PM, Jerzy Karczmarczuk < jerzy.karczmarc...@unicaen.fr> wrote: > > Le 20/03/2015 16:57, Ryan Nelson a écrit : > > For me, if I change the script from the PR to what is shown below, > > everything works fine in both Python 2.7 and 3.4 (Anaconda > > environments, everything updated): > > ## > > url = 'http://www.libpng.org/pub/png/img_png/pngnow.png' > > try: > > import urllib2 > > data = urllib2.urlopen(url) > > except Exception: > > import urllib.request > > from io import BytesIO > > data = BytesIO(urllib.request.urlopen(url).read()) > > > > from matplotlib import pyplot > > > > image = pyplot.imread(data) # crash on py3.x > > pyplot.imshow(image) > > pyplot.show() > > # > > But as you can see, the Python 3 version requires the addition of > > BytesIO and read(). I take it that this is not supposed to be the case. > > It works for X.png, not for X.jpg. The call of imread() fails then. > Tested also under 3.4/Anaconda. > > Jerzy Karczmarczuk > > > > -- > Dive into the World of Parallel Programming The Go Parallel Website, > sponsored > by Intel and developed in partnership with Slashdot Media, is your hub for > all > things parallel software development, from weekly thought leadership blogs > to > news, videos, case studies, tutorials and more. Take a look and join the > conversation now. http://goparallel.sourceforge.net/ > ___ > Matplotlib-users mailing list > Matplotlib-users@lists.sourceforge.net > https://lists.sourceforge.net/lists/listinfo/matplotlib-users > -- Dive into the World of Parallel Programming The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Best way to display image from URL in Python3
Despite my grumping earlier, a PR that makes URLs just work is probably a good idea and would be merged. Tom On Fri, Mar 20, 2015 at 3:59 PM Jerzy Karczmarczuk < jerzy.karczmarc...@unicaen.fr> wrote: > > Le 20/03/2015 16:57, Ryan Nelson a écrit : > > For me, if I change the script from the PR to what is shown below, > > everything works fine in both Python 2.7 and 3.4 (Anaconda > > environments, everything updated): > > ## > > url = 'http://www.libpng.org/pub/png/img_png/pngnow.png' > > try: > > import urllib2 > > data = urllib2.urlopen(url) > > except Exception: > > import urllib.request > > from io import BytesIO > > data = BytesIO(urllib.request.urlopen(url).read()) > > > > from matplotlib import pyplot > > > > image = pyplot.imread(data) # crash on py3.x > > pyplot.imshow(image) > > pyplot.show() > > # > > But as you can see, the Python 3 version requires the addition of > > BytesIO and read(). I take it that this is not supposed to be the case. > > It works for X.png, not for X.jpg. The call of imread() fails then. > Tested also under 3.4/Anaconda. > > Jerzy Karczmarczuk > > > > -- > Dive into the World of Parallel Programming The Go Parallel Website, > sponsored > by Intel and developed in partnership with Slashdot Media, is your hub for > all > things parallel software development, from weekly thought leadership blogs > to > news, videos, case studies, tutorials and more. Take a look and join the > conversation now. http://goparallel.sourceforge.net/ > ___ > Matplotlib-users mailing list > Matplotlib-users@lists.sourceforge.net > https://lists.sourceforge.net/lists/listinfo/matplotlib-users > -- Dive into the World of Parallel Programming The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Best way to display image from URL in Python3
Le 20/03/2015 16:57, Ryan Nelson a écrit : > For me, if I change the script from the PR to what is shown below, > everything works fine in both Python 2.7 and 3.4 (Anaconda > environments, everything updated): > ## > url = 'http://www.libpng.org/pub/png/img_png/pngnow.png' > try: > import urllib2 > data = urllib2.urlopen(url) > except Exception: > import urllib.request > from io import BytesIO > data = BytesIO(urllib.request.urlopen(url).read()) > > from matplotlib import pyplot > > image = pyplot.imread(data) # crash on py3.x > pyplot.imshow(image) > pyplot.show() > # > But as you can see, the Python 3 version requires the addition of > BytesIO and read(). I take it that this is not supposed to be the case. It works for X.png, not for X.jpg. The call of imread() fails then. Tested also under 3.4/Anaconda. Jerzy Karczmarczuk -- Dive into the World of Parallel Programming The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Best way to display image from URL in Python3
I can understand that switching from Py 2 to 3 is going to require a change from urllib2.urlopen to urllib.requests.urlopen, but the addition of BytesIO and read() makes the transition tricky. It was not obvious to me why that wouldn't work right off the bat, which is why I had to dig up that PR and SO post. As an alternate question, then: would a PR be welcome that makes it so that URL info can be passed directly to the imread function? There's already a test to see if fname is a string. Maybe a quick check to see if it starts with "http". Then imread could handle all of this business internally. Thanks Ryan On Fri, Mar 20, 2015 at 12:24 PM, Thomas Caswell wrote: > I think `six` (which we use to smooth over the 2/3 changes) has a way of > dealing with atleast the urllib renaming . > > On Fri, Mar 20, 2015 at 11:58 AM Ryan Nelson > wrote: > >> For me, if I change the script from the PR to what is shown below, >> everything works fine in both Python 2.7 and 3.4 (Anaconda environments, >> everything updated): >> ## >> url = 'http://www.libpng.org/pub/png/img_png/pngnow.png' >> try: >> import urllib2 >> data = urllib2.urlopen(url) >> except Exception: >> import urllib.request >> from io import BytesIO >> data = BytesIO(urllib.request.urlopen(url).read()) >> >> from matplotlib import pyplot >> >> image = pyplot.imread(data) # crash on py3.x >> pyplot.imshow(image) >> pyplot.show() >> # >> But as you can see, the Python 3 version requires the addition of BytesIO >> and read(). I take it that this is not supposed to be the case. >> >> Ryan >> >> On Fri, Mar 20, 2015 at 11:48 AM, Ryan Nelson >> wrote: >> >>> Thanks, Ben. I should have made that more clear. If I run the code from >>> the PR, I get the following error: >>> >>> Traceback (most recent call last): >>> File "junk.py", line 11, in >>> image = pyplot.imread(data) # crash on py3.x >>> File >>> "/home/nelson/apps/miniconda/lib/python3.4/site-packages/matplotlib/pyplot.py", >>> line 2215, in imread >>> return _imread(*args, **kwargs) >>> File >>> "/home/nelson/apps/miniconda/lib/python3.4/site-packages/matplotlib/image.py", >>> line 1270, in imread >>> return handler(fname) >>> RuntimeError: _image_module::readpng: file not recognized as a PNG file >>> >>> My code that I'm trying to port essentially does the same thing, and I >>> get the same error. I ran this example just now from Anaconda Python 3.4 >>> install with MPL 1.4.3. >>> >>> My impression from the PR was that this should work out of the box now. >>> I figured that maybe that was not quite the case. The implementations >>> between Py2 and 3 are quite different. Figured there must be a different >>> way that I wasn't aware of. >>> >>> Ryan >>> >>> On Fri, Mar 20, 2015 at 9:51 AM, Benjamin Root wrote: >>> According to the PR you reference, the fix for this was merged back in Jan 2013, so that means that this fix is in version 1.2.x and up. Are you saying that you still can't do imread(urllib.request.urlopen(url))? On Thu, Mar 19, 2015 at 8:54 PM, Ryan Nelson wrote: > Hello all, > > I'm porting over some code that used Py2.7 urllib2.urlopen(url) to > grab some image data from the net and load with pyplot.imread. It doesn't > work quite right in Py3.4. I found a couple of refs: > > https://github.com/matplotlib/matplotlib/pull/1650 > > http://stackoverflow.com/questions/15183170/python-crash-when-downloading-image-as-numpy-array > > They suggest io.BytesIO(urllib.request.urlopen(url).read()) as a > replacement for Py3. Is this the best practice? Does anyone know a simpler > way to do this? > > Ryan > > > -- > Dive into the World of Parallel Programming The Go Parallel Website, > sponsored > by Intel and developed in partnership with Slashdot Media, is your hub > for all > things parallel software development, from weekly thought leadership > blogs to > news, videos, case studies, tutorials and more. Take a look and join > the > conversation now. http://goparallel.sourceforge.net/ > ___ > Matplotlib-users mailing list > Matplotlib-users@lists.sourceforge.net > https://lists.sourceforge.net/lists/listinfo/matplotlib-users > > >>> >> >> -- >> Dive into the World of Parallel Programming The Go Parallel Website, >> sponsored >> by Intel and developed in partnership with Slashdot Media, is your hub >> for all >> things parallel software development, from weekly thought leadership >> blogs to >> news, videos, case studies, tutorials and more. Take a look and join the >> conversation now. http://goparallel.sourceforge.net/ >> __
Re: [Matplotlib-users] Best way to display image from URL in Python3
I think `six` (which we use to smooth over the 2/3 changes) has a way of dealing with atleast the urllib renaming . On Fri, Mar 20, 2015 at 11:58 AM Ryan Nelson wrote: > For me, if I change the script from the PR to what is shown below, > everything works fine in both Python 2.7 and 3.4 (Anaconda environments, > everything updated): > ## > url = 'http://www.libpng.org/pub/png/img_png/pngnow.png' > try: > import urllib2 > data = urllib2.urlopen(url) > except Exception: > import urllib.request > from io import BytesIO > data = BytesIO(urllib.request.urlopen(url).read()) > > from matplotlib import pyplot > > image = pyplot.imread(data) # crash on py3.x > pyplot.imshow(image) > pyplot.show() > # > But as you can see, the Python 3 version requires the addition of BytesIO > and read(). I take it that this is not supposed to be the case. > > Ryan > > On Fri, Mar 20, 2015 at 11:48 AM, Ryan Nelson > wrote: > >> Thanks, Ben. I should have made that more clear. If I run the code from >> the PR, I get the following error: >> >> Traceback (most recent call last): >> File "junk.py", line 11, in >> image = pyplot.imread(data) # crash on py3.x >> File >> "/home/nelson/apps/miniconda/lib/python3.4/site-packages/matplotlib/pyplot.py", >> line 2215, in imread >> return _imread(*args, **kwargs) >> File >> "/home/nelson/apps/miniconda/lib/python3.4/site-packages/matplotlib/image.py", >> line 1270, in imread >> return handler(fname) >> RuntimeError: _image_module::readpng: file not recognized as a PNG file >> >> My code that I'm trying to port essentially does the same thing, and I >> get the same error. I ran this example just now from Anaconda Python 3.4 >> install with MPL 1.4.3. >> >> My impression from the PR was that this should work out of the box now. I >> figured that maybe that was not quite the case. The implementations between >> Py2 and 3 are quite different. Figured there must be a different way that I >> wasn't aware of. >> >> Ryan >> >> On Fri, Mar 20, 2015 at 9:51 AM, Benjamin Root wrote: >> >>> According to the PR you reference, the fix for this was merged back in >>> Jan 2013, so that means that this fix is in version 1.2.x and up. Are you >>> saying that you still can't do imread(urllib.request.urlopen(url))? >>> >>> On Thu, Mar 19, 2015 at 8:54 PM, Ryan Nelson >>> wrote: >>> Hello all, I'm porting over some code that used Py2.7 urllib2.urlopen(url) to grab some image data from the net and load with pyplot.imread. It doesn't work quite right in Py3.4. I found a couple of refs: https://github.com/matplotlib/matplotlib/pull/1650 http://stackoverflow.com/questions/15183170/python-crash-when-downloading-image-as-numpy-array They suggest io.BytesIO(urllib.request.urlopen(url).read()) as a replacement for Py3. Is this the best practice? Does anyone know a simpler way to do this? Ryan -- Dive into the World of Parallel Programming The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users >>> >> > > -- > Dive into the World of Parallel Programming The Go Parallel Website, > sponsored > by Intel and developed in partnership with Slashdot Media, is your hub for > all > things parallel software development, from weekly thought leadership blogs > to > news, videos, case studies, tutorials and more. Take a look and join the > conversation now. http://goparallel.sourceforge.net/ > ___ > Matplotlib-users mailing list > Matplotlib-users@lists.sourceforge.net > https://lists.sourceforge.net/lists/listinfo/matplotlib-users > -- Dive into the World of Parallel Programming The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Best way to display image from URL in Python3
For me, if I change the script from the PR to what is shown below, everything works fine in both Python 2.7 and 3.4 (Anaconda environments, everything updated): ## url = 'http://www.libpng.org/pub/png/img_png/pngnow.png' try: import urllib2 data = urllib2.urlopen(url) except Exception: import urllib.request from io import BytesIO data = BytesIO(urllib.request.urlopen(url).read()) from matplotlib import pyplot image = pyplot.imread(data) # crash on py3.x pyplot.imshow(image) pyplot.show() # But as you can see, the Python 3 version requires the addition of BytesIO and read(). I take it that this is not supposed to be the case. Ryan On Fri, Mar 20, 2015 at 11:48 AM, Ryan Nelson wrote: > Thanks, Ben. I should have made that more clear. If I run the code from > the PR, I get the following error: > > Traceback (most recent call last): > File "junk.py", line 11, in > image = pyplot.imread(data) # crash on py3.x > File > "/home/nelson/apps/miniconda/lib/python3.4/site-packages/matplotlib/pyplot.py", > line 2215, in imread > return _imread(*args, **kwargs) > File > "/home/nelson/apps/miniconda/lib/python3.4/site-packages/matplotlib/image.py", > line 1270, in imread > return handler(fname) > RuntimeError: _image_module::readpng: file not recognized as a PNG file > > My code that I'm trying to port essentially does the same thing, and I get > the same error. I ran this example just now from Anaconda Python 3.4 > install with MPL 1.4.3. > > My impression from the PR was that this should work out of the box now. I > figured that maybe that was not quite the case. The implementations between > Py2 and 3 are quite different. Figured there must be a different way that I > wasn't aware of. > > Ryan > > On Fri, Mar 20, 2015 at 9:51 AM, Benjamin Root wrote: > >> According to the PR you reference, the fix for this was merged back in >> Jan 2013, so that means that this fix is in version 1.2.x and up. Are you >> saying that you still can't do imread(urllib.request.urlopen(url))? >> >> On Thu, Mar 19, 2015 at 8:54 PM, Ryan Nelson >> wrote: >> >>> Hello all, >>> >>> I'm porting over some code that used Py2.7 urllib2.urlopen(url) to grab >>> some image data from the net and load with pyplot.imread. It doesn't work >>> quite right in Py3.4. I found a couple of refs: >>> >>> https://github.com/matplotlib/matplotlib/pull/1650 >>> >>> http://stackoverflow.com/questions/15183170/python-crash-when-downloading-image-as-numpy-array >>> >>> They suggest io.BytesIO(urllib.request.urlopen(url).read()) as a >>> replacement for Py3. Is this the best practice? Does anyone know a simpler >>> way to do this? >>> >>> Ryan >>> >>> >>> -- >>> Dive into the World of Parallel Programming The Go Parallel Website, >>> sponsored >>> by Intel and developed in partnership with Slashdot Media, is your hub >>> for all >>> things parallel software development, from weekly thought leadership >>> blogs to >>> news, videos, case studies, tutorials and more. Take a look and join the >>> conversation now. http://goparallel.sourceforge.net/ >>> ___ >>> Matplotlib-users mailing list >>> Matplotlib-users@lists.sourceforge.net >>> https://lists.sourceforge.net/lists/listinfo/matplotlib-users >>> >>> >> > -- Dive into the World of Parallel Programming The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Best way to display image from URL in Python3
Thanks, Ben. I should have made that more clear. If I run the code from the PR, I get the following error: Traceback (most recent call last): File "junk.py", line 11, in image = pyplot.imread(data) # crash on py3.x File "/home/nelson/apps/miniconda/lib/python3.4/site-packages/matplotlib/pyplot.py", line 2215, in imread return _imread(*args, **kwargs) File "/home/nelson/apps/miniconda/lib/python3.4/site-packages/matplotlib/image.py", line 1270, in imread return handler(fname) RuntimeError: _image_module::readpng: file not recognized as a PNG file My code that I'm trying to port essentially does the same thing, and I get the same error. I ran this example just now from Anaconda Python 3.4 install with MPL 1.4.3. My impression from the PR was that this should work out of the box now. I figured that maybe that was not quite the case. The implementations between Py2 and 3 are quite different. Figured there must be a different way that I wasn't aware of. Ryan On Fri, Mar 20, 2015 at 9:51 AM, Benjamin Root wrote: > According to the PR you reference, the fix for this was merged back in Jan > 2013, so that means that this fix is in version 1.2.x and up. Are you > saying that you still can't do imread(urllib.request.urlopen(url))? > > On Thu, Mar 19, 2015 at 8:54 PM, Ryan Nelson > wrote: > >> Hello all, >> >> I'm porting over some code that used Py2.7 urllib2.urlopen(url) to grab >> some image data from the net and load with pyplot.imread. It doesn't work >> quite right in Py3.4. I found a couple of refs: >> >> https://github.com/matplotlib/matplotlib/pull/1650 >> >> http://stackoverflow.com/questions/15183170/python-crash-when-downloading-image-as-numpy-array >> >> They suggest io.BytesIO(urllib.request.urlopen(url).read()) as a >> replacement for Py3. Is this the best practice? Does anyone know a simpler >> way to do this? >> >> Ryan >> >> >> -- >> Dive into the World of Parallel Programming The Go Parallel Website, >> sponsored >> by Intel and developed in partnership with Slashdot Media, is your hub >> for all >> things parallel software development, from weekly thought leadership >> blogs to >> news, videos, case studies, tutorials and more. Take a look and join the >> conversation now. http://goparallel.sourceforge.net/ >> ___ >> Matplotlib-users mailing list >> Matplotlib-users@lists.sourceforge.net >> https://lists.sourceforge.net/lists/listinfo/matplotlib-users >> >> > -- Dive into the World of Parallel Programming The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Best way to display image from URL in Python3
According to the PR you reference, the fix for this was merged back in Jan 2013, so that means that this fix is in version 1.2.x and up. Are you saying that you still can't do imread(urllib.request.urlopen(url))? On Thu, Mar 19, 2015 at 8:54 PM, Ryan Nelson wrote: > Hello all, > > I'm porting over some code that used Py2.7 urllib2.urlopen(url) to grab > some image data from the net and load with pyplot.imread. It doesn't work > quite right in Py3.4. I found a couple of refs: > > https://github.com/matplotlib/matplotlib/pull/1650 > > http://stackoverflow.com/questions/15183170/python-crash-when-downloading-image-as-numpy-array > > They suggest io.BytesIO(urllib.request.urlopen(url).read()) as a > replacement for Py3. Is this the best practice? Does anyone know a simpler > way to do this? > > Ryan > > > -- > Dive into the World of Parallel Programming The Go Parallel Website, > sponsored > by Intel and developed in partnership with Slashdot Media, is your hub for > all > things parallel software development, from weekly thought leadership blogs > to > news, videos, case studies, tutorials and more. Take a look and join the > conversation now. http://goparallel.sourceforge.net/ > ___ > Matplotlib-users mailing list > Matplotlib-users@lists.sourceforge.net > https://lists.sourceforge.net/lists/listinfo/matplotlib-users > > -- Dive into the World of Parallel Programming The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
