I can't reproduce this on version = 1.1.0. What version of matplotlib
are you using?
On 11 June 2012 17:23, Gustavo Goretkin gustavo.goret...@gmail.com wrote:
The problem is that the function in _path.cpp expects a path radius
argument, r.
Here is the signature:
point_in_path(double x,
I can confirm the bad link.
Would you mind opening a new issue on github for this?
github.com/matplotlib/matplotlib/issues/new
Thanks,
On 19 July 2012 10:15, Francesco Montesano franz.berges...@gmail.com wrote:
Hi,
roaming through the gallery I've found that in
Ah, sorry, forgot to reply to all. Please see the solution I provided to Jon.
-- Forwarded message --
Date: 22 July 2012 15:08
Subject: Re: [Matplotlib-users] How to Change Axis Tick Mark Labels
Sounds like you want to use a FunctionFormatter rather than modifying
the ticks
Looks like your very close.
I needed to change the months to short English form, change the line
ax3.grid('True') to ax3.grid(True)
and add the line
ax3.axvspan(*mdates.datestr2num(['05/18/2012', '06/30/2012']),
facecolor='g', alpha=0.5)
To get the box on the lower plot.
Hope that
- Apr, Mai - May??? ...still did not work.
From: Phil Elson pelson@gmail.com
To: Luciano Fleischfresser l...@utfpr.edu.br
Cc: Matplotlib-users@lists.sourceforge.net
Matplotlib-users@lists.sourceforge.net
Sent: Monday, July 23, 2012 5:45 PM
Subject: Re
I don't have a good answer to this and have had to implement such a
thing in an outstanding pull request (in my case, I have a figure
which has been un-pickled and needs re-attaching to pyplot).
My proposed mechanism goes something like:
figure = matplotlib.figure.Figure(...)
import
I'm not aware of an rc param for this. The relevant github issue:
https://github.com/matplotlib/matplotlib/issues/461
Regards,
Phil
On 19 August 2012 21:27, Christopher Graves christoph.gra...@gmail.comwrote:
Using matplotlib 1.1.1.
If one runs the following code:
from pylab import *
This seems to a be common misconception...
I guess in future, we could add a check to the add_patch method to see if
the given artist already has an associated Axes, and if it does, emit a
warning.
On 7 September 2012 07:42, Eric Firing efir...@hawaii.edu wrote:
On 2012/09/06 8:35 PM, jonasr
Ben, on master scatter legends are broken. A pull request (I can't remember
which, and github is down, possibly #1176) fixes this (obviously, the PR is
marked as release critical for 1.2).
I have confirmed, that even once fixed on master, the scatter legend
handler does not take notice of the
Thanks for raising this. I have simplified and opened an issue for the bug (
https://github.com/matplotlib/matplotlib/issues/1246) and will be looking
at this asap.
All the best,
Phil
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Most devs has no
On 14 September 2012 17:53, Scott Lasley slas...@space.umd.edu wrote:
On Sep 14, 2012, at 5:02 AM, Phil Elson pelson@gmail.com wrote:
Thanks for raising this. I have simplified and opened an issue for the
bug (https://github.com/matplotlib/matplotlib/issues/1246) and will be
looking
Note, however, code has been improved for the 1.2.0 release to make it
easier to modify the set of buttons that are used. In backend_bases.py,
look for the NavigationToolbar2 class.
Ah yes! I knew I did that for a good reason. :-) Good thinking Ben!
Personally, I am not a fan of adding a window specific keyword to the
figure function (although there may be some there already).
With 1.2 you can use Matthew Emmett/Paul Ivanov's awesome new context
manager to remove the toolbar for the duration of the with statement:
import matplotlib.pyplot
This works for me with 1.2 (not tested before that):
import matplotlib.pyplot as plt
import numpy as np
x = np.array([0, 1, None, 1, 0])
y = np.array([0, 1, None, 0, 1])
plt.plot(x, y)
plt.show()
I get two distinct lines crossing each other at (0.5, 0.5)
HTH,
Nice challenge Fernando!
Damon, I love the solution! I do wonder whether we could do some
quirky transform on the lines to achieve a similar result, rather than
manipulating the data before plotting it. The benefit is that
everything should then get randomly Xkcd-ed automatically - maybe I
will
To plot a line using pyplot.plot you need an array/list of x coordinates
and an array/list of y coordinates.
So if you have:
data = [[64, 13], [66, 22], [68, 9], [70, 11], [72, 8], [74, 10], [76, 11],
[78, 8], [80, 9], [82, 9], [84, 15], [86, 13], [88, 5], [90,
9], [92, 13],
If nothing speaks against it, i could do a pull request.
If you are willing, I would encourage you to do that, or at least make a
branch in your matplotlib fork and post the diff URL here. That way we can
discuss the pros cons in-line, even if it means that we do no actually
merge the PR (that
I can certainly see the benefit. As Mike said, I don't think I would use it
myself, but I could see non-python users finding it useful.
Personally, I think this would be a nice extension that doesn't have to
live in the core matplotlib code base. That way release cycles and testing
can be done
Good idea. If the png version works then the jpg version should also be
made to work,
Would you be willing to open up an issue for the feature request? :
https://github.com/matplotlib/matplotlib/issues/new
If your ready and willing to implement such a thing, that would be even
better (just open
Hi Brandon,
I notice that this is cross-posted on StackOverflow (
http://stackoverflow.com/questions/13132194/type-1-fonts-with-log-graphs).
Personally, I have no problem with cross posting, but to save two people
having to answer the same question, I would make sure it was explicit that
this had
Hi Brad,
I didn't quite follow what it was that you were trying to achieve, but the
following example may be of interest to you:
import matplotlib.pyplot as plt
from matplotlib.patches import Ellipse, Circle
import matplotlib.transforms as mtrans
fig = plt.figure()
ax1 =
The original question was raised in a mpl ticket:
https://github.com/matplotlib/matplotlib/issues/1513
My original answer there (copied pasted):
The bbox_inches='tight' option to savefig does some analysis on the artists
visible on your plot and figures out the minimum bounding box needed to
Hi Pierre,
Thanks for raising this (sorry we haven't got back to you sooner).
The mailing list isn't dead, but the archiving link certainly makes it look
like it is. I've just submitted a pull request (
https://github.com/matplotlib/matplotlib/pull/1540) to get the mpl docs to
link to the nabble
As of matplotlib v1.2.0 you can hatch a contour set directly. There is an
example in the gallery:
http://matplotlib.org/examples/pylab_examples/contourf_hatching.html
Hope that helps,
Phil
On 5 December 2012 17:28, spencerahill spencerah...@gmail.com wrote:
Jae-Joon Lee wrote
On Thu, Sep
Joe Kington's answer is the best solution I've seen to this problem:
http://stackoverflow.com/questions/13622909/matplotlib-how-to-colorize-a-large-number-of-line-segments-as-independent-gradi
There is also an example in the gallery:
Perhaps something like:
from matplotlib import pyplot as plt
from netCDF4 import Dataset
import numpy as np
url=*'
http://www.marine.csiro.au/dods/nph-dods/dods-data/climatology-netcdf/levitus_monthly_temp_98.nc
'*
ds = Dataset(url)
temp = ds.variables[*'TEMP'*]
lats =
, Phil Elson pelson@gmail.com wrote:
Perhaps something like:
from matplotlib import pyplot as plt
from netCDF4 import Dataset
import numpy as np
url=*'
http://www.marine.csiro.au/dods/nph-dods/dods-data/climatology-netcdf/levitus_monthly_temp_98.nc
'*
ds = Dataset(url)
temp
Sounds like a nice feature if it doesn't already exist. At first glance,
I'd say this was a good candidate for the low-hanging fruit label (
https://github.com/matplotlib/matplotlib/issues?labels=low+hanging+fruitpage=1state=open)
for which we have tickets which have a low matplotlib contribution
The key thing to know about normal Artists is that they can have *just
one*transform (to take an artist's coordinates into pixel space), so
whilst
there is no error when you do it, it is not possible to add the same artist
to multiple Axes and have the desired effect.
To answer your question, try
Hi Sudheer,
Try the interactive mode (
http://matplotlib.org/api/pyplot_api.html#matplotlib.pyplot.ion):
import matplotlib.pyplot as plt
plt.ion()
plt.plot(range(10))
[matplotlib.lines.Line2D object at 0x1c565d0]
**a figure pops up here and hands you back the python command line**
Hi Mike,
Do you have any code or an image to show the problem?
Cheers,
On 11 March 2013 20:44, Hearne, Mike mhea...@usgs.gov wrote:
I have an issue with basemap.imshow() at higher latitudes - namely the
image (high-res topography, in this case) becomes distorted with
respect to the
I don't know of any reason why one shouldn't be able to use the wxAgg
backend interactively.
This looks like a bug to me. Would you mind adding this as an issue on the
github issue tracker?
Thanks,
On 11 March 2013 19:06, Brendan Barnwell brenb...@brenbarn.net wrote:
I'm 64-bit
://oppamthadathil.tripod.com
***
--
*From:* Phil Elson pelson@gmail.com
*To:* Sudheer Joseph sudheer.jos...@yahoo.com
*Cc:* matplotlib-users@lists.sourceforge.net
matplotlib-users@lists.sourceforge.net
Thanks for this Joe, mpldatacursor looks like an excellent piece of work -
I for one will be installing and using it regularly.
Thanks for sharing!
On 13 March 2013 03:58, Joe Kington joferking...@gmail.com wrote:
I recently got around to polishing up a snippet I've been using for quite
Doesn't look like you're using math.usetex therefore are not actually
using latex, but mpl's stripped down tex implementation.
Try setting usetex to True, or alternatively I think you could use \mathrm
instead of \text to get non mathematical text.
HTH
On 30 March 2013 11:43, Pawel Chojnacki
Hi Derek,
What are we looking at here?
The following code:
import matplotlib.pyplot as plt
import matplotlib.transforms as mtrans
import numpy as np
plt.figure()
ax = plt.subplot(111)
base_trans = ax.transData
mtx = np.array([[1,1,0],
[0,1,0],
[0,0,1]])
tr =
Hi Mark,
Thanks for persevering :-)
What is it you want to achieve? Is it that you just want the last day of
each month as the located value?
Changing your locator to:
ax.xaxis.set_major_locator(MonthLocator(bymonthday = -1))
Seems to do the trick for me (I've never looked at the mpl date
Thanks Derek John.
Very strange. Here's my setup:
import matplotlib
matplotlib.__version__
'1.2.0'
matplotlib.get_backend()
'TkAgg'
Would you mind providing all of the relevant details suggested in
http://matplotlib.org/faq/troubleshooting_faq.html#troubleshooting, along
with the code to
Agreed. I've seen this a couple of times but never reproduced it so
elegantly. Would you mind opening up an issue on github - this is
definitely a bug (http://matplotlib.org/faq/troubleshooting_faq.html).
Thanks!
P.S. Welcome to the mailinglist :-)
On 31 May 2013 16:02, Skip Montanaro
Hi Martin,
Thanks for this - we are really interested in speeding up the scatter and
barchart plotting with large data sets. In fact, we've done some work (
https://github.com/matplotlib/matplotlib/pull/2156) recently to make the
situation better.
I'd really like to review these changes (against
Great question. The contour set itself does not have a set_clip_path method
but you can iterate over each of the contour collections and set their
respective clip paths, i.e.:
cs = plt.contourf(data)
for collection in cs.collections:
collection.set_clip_path(poly)
Of course, you can use this
shown), and I hope the development goes well.
Thanks,
Alex
On Mon, Sep 2, 2013 at 2:33 AM, Phil Elson pelson@gmail.com wrote:
Great question. The contour set itself does not have a set_clip_path
method but you can iterate over each of the contour collections and set
their respective clip
Hi Kai,
I'm afraid I've never heard of this one. Do you have a full error log?
Thanks,
On 26 January 2014 02:40, kaiw...@genetics.ac.cn wrote:
Hi,
I'm trying to use matplotlib to generate pictures for my website view. The
framwork I use is pyramid. But I got an error when I try to
As with most other artists, you should be able to just call remove on the
resulting artist.
e.g.
im = plt.imshow(...)
...
im.remove()
HTH
On 2 January 2014 11:58, flambert franz_lambert_en...@yahoo.de wrote:
Hi,
Does somebody knows how can I remove a backgroundimage. I set the image
Thanks for this Vlastimil, looks like there is either a subtlety beyond my
font knowledge or a bug here - mdboom, did you have any ideas? Otherwise I
think we need a github issue for this.
Cheers,
On 4 January 2014 19:37, Vlastimil Brom vlastimil.b...@gmail.com wrote:
Hi all,
after upgrading
This is a bit of a surprise. Sounds like it could have something to do with
matplotlib's build, or that of some of its dependencies, so may need
reporting to Gentoo once we've dug a little further. It could be a really
tricky one to diagnose without being able to reproduce locally, but - is
the
I fixed an issue related to this (I too was producing map tiles) in
matplotlib v1.2 I believe.
The original issue can be found at
https://github.com/matplotlib/matplotlib/pull/1591 and so I suggest this
might not be an issue with matplotlib = v1.3.
Incidentally, if you are producing map tiles
Cool notebook. I took the liberty of giving it a go with cartopy, and you
can see the results here http://nbviewer.ipython.org/gist/pelson/10822698
I'd agree that the issue you linked to does look very similar to the issue
you are seeing, so I think this is very likely a bug.
Cheers,
On 16
Hi Chao,
The warning you are getting:
WARNING: x coordinate not monotonically increasing - contour plot
may not be what you expect. If it looks odd, your can either
adjust the map projection region to be consistent with your data, or
(if your data is on a global lat/lon grid) use the shiftgrid
Also note, you can just call plt.xkcd() and it will turn on the setting
globally for that session.
On 4 October 2014 00:11, Paul Hobson pmhob...@gmail.com wrote:
That's what the `with` statement allows you do.
Say you have a function that does some plotting and returns a figure --
call it
On 10 October 2014 19:10, Thomas Caswell tcasw...@gmail.com wrote:
I suspect a better fix is to change all of the staticmethods -
classmethods
+1
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There will be an open source Python sprint, hosted by Bloomberg, this
weekend in London. The event will be attended by core developers of many of
the major scientific Python packages (IPython, numpy, scipy, pandas,
scikit-learn) who will act as mentors to those who would like to get
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Sorry its taken so long to get an answer, but essentially you want to
concatenate the outer coordinates with the inner ones (reversed) to
indicate that it is a hole. There is a pretty (simple) useful example that
I added a few years ago for demonstrating the use of paths for markers:
vertices / paths that are detected to be inside an outline as the star in
this example?
-Denis
2014-12-22 12:09 GMT+01:00 Phil Elson pelson@gmail.com:
Sorry its taken so long to get an answer, but essentially you want to
concatenate the outer coordinates with the inner ones (reversed
.
Finally, to all those taking some time off this festive season, I wish you
a very happy holiday and wish you all the best for the new year.
Phil Elson
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Awesome work! Full credit to Tom who has driven this release.
The nbagg backend is looking great - some pretty swish new features thanks
to hard work from Steven Silvester and Thomas Caswell!
On 2 February 2015 at 10:58, Jens Nielsen jenshniel...@gmail.com wrote:
Thanks Tom,
I ran the test
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