Re: Admittance formula for branches with transformers

2016-09-19 Thread Ray Zimmerman
It’s a simple summation of the corresponding diagonal elements from the branch 
admittance matrix in (3.2), plus any bus shunt elements.

Ray


> On Sep 3, 2016, at 11:59 AM, davor sutic  wrote:
> 
> I did a thorough study of makeYbus() (both a code analysis and step-by-step 
> executions) and was able to answer the majority of my questions. However, I 
> still can't get the mathematical sense on how a diagonal element with 
> multiple transformers is treated.
> 
> As an example consider case14.m bus 4, here is stripped down version of its 
> portion of the branch input matrix:
> 
> fbus |  tbus |  r   | x   | b  |  ratio  |  angle
> 2|  4|  0.05811 | 0.17632 | 0.034  |  0  |  0
> 3|  4|  0.06701 | 0.17103 | 0.0128 |  0  |  0
> 4|  5|  0.01335 | 0.04211 | 0  |  0  |  0
> 4|  7|  0   | 0.20912 | 0  |  0.978  |  0
> 4|  9|  0   | 0.55618 | 0  |  0.969  |  0
> 
> There are 5 lines that meet at bus 4, 2 have transformers (albeit with no 
> phase shift, but that shouldn't be important) and of the remaining 3, 2 have 
> line charging. 
> 
> What is the general formula for a diagonal element?
> 
> Thanks a lot
> 
> 
> On Fri, Aug 26, 2016 at 7:58 PM, Abhyankar, Shrirang G.  > wrote:
> Please take a look at the function makeYbus().
> 
> > On Aug 26, 2016, at 10:05 AM, davor sutic  > > wrote:
> >
> > I'm trying to understand the effects of having a transformer connected to a 
> > branch on the implicated admittance matrix. In the MatPower manual, section 
> > 3.2, equation 3.2 describes such a relation for a 2x2 branch admittance 
> > matrix.
> >
> > I'm interested in the general form of the (diagonal and off-diagonal) 
> > elements of an admittance matrix, when multiple branches have transformers 
> > attached. Particularly the diagonal elements are confusing, how are the 
> > elements summed up, if multiple have transformers?
> >
> > Further, in the test case files, the absence of a transformer is indicated 
> > with its ratio and angle set to 0. In the mentioned equation (3.2) that 
> > would cause problems when dividing with 0. So another question is how are 
> > those elements treated in the light of formula 3.2?
> >
> > Thanks a lot.
> 
> 
> 



Re: Admittance formula for branches with transformers

2016-09-03 Thread davor sutic
I did a thorough study of makeYbus() (both a code analysis and step-by-step
executions) and was able to answer the majority of my questions. However, I
still can't get the mathematical sense on how a diagonal element with
multiple transformers is treated.

As an example consider case14.m bus 4, here is stripped down version of its
portion of the branch input matrix:

fbus |  tbus |  r   | x   | b  |  ratio  |  angle
2|  4|  0.05811 | 0.17632 | 0.034  |  0  |  0
3|  4|  0.06701 | 0.17103 | 0.0128 |  0  |  0
4|  5|  0.01335 | 0.04211 | 0  |  0  |  0
4|  7|  0   | 0.20912 | 0  |  0.978  |  0
4|  9|  0   | 0.55618 | 0  |  0.969  |  0

There are 5 lines that meet at bus 4, 2 have transformers (albeit with no
phase shift, but that shouldn't be important) and of the remaining 3, 2
have line charging.

What is the general formula for a diagonal element?

Thanks a lot


On Fri, Aug 26, 2016 at 7:58 PM, Abhyankar, Shrirang G. 
wrote:

> Please take a look at the function makeYbus().
>
> > On Aug 26, 2016, at 10:05 AM, davor sutic  wrote:
> >
> > I'm trying to understand the effects of having a transformer connected
> to a branch on the implicated admittance matrix. In the MatPower manual,
> section 3.2, equation 3.2 describes such a relation for a 2x2 branch
> admittance matrix.
> >
> > I'm interested in the general form of the (diagonal and off-diagonal)
> elements of an admittance matrix, when multiple branches have transformers
> attached. Particularly the diagonal elements are confusing, how are the
> elements summed up, if multiple have transformers?
> >
> > Further, in the test case files, the absence of a transformer is
> indicated with its ratio and angle set to 0. In the mentioned equation
> (3.2) that would cause problems when dividing with 0. So another question
> is how are those elements treated in the light of formula 3.2?
> >
> > Thanks a lot.
>
>
>


Re: Admittance formula for branches with transformers

2016-08-26 Thread Abhyankar, Shrirang G.
Please take a look at the function makeYbus(). 

> On Aug 26, 2016, at 10:05 AM, davor sutic  wrote:
> 
> I'm trying to understand the effects of having a transformer connected to a 
> branch on the implicated admittance matrix. In the MatPower manual, section 
> 3.2, equation 3.2 describes such a relation for a 2x2 branch admittance 
> matrix.
> 
> I'm interested in the general form of the (diagonal and off-diagonal) 
> elements of an admittance matrix, when multiple branches have transformers 
> attached. Particularly the diagonal elements are confusing, how are the 
> elements summed up, if multiple have transformers?
> 
> Further, in the test case files, the absence of a transformer is indicated 
> with its ratio and angle set to 0. In the mentioned equation (3.2) that would 
> cause problems when dividing with 0. So another question is how are those 
> elements treated in the light of formula 3.2?
> 
> Thanks a lot.